The goal is to find $$$\sum^{X-1}_{i=0}A^{i} mod m$$$
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my solution of Atcoder Beginner Contest 293 E
The goal is to find $$$\sum^{X-1}_{i=0}A^{i} mod m$$$
Rev. | Lang. | By | When | Δ | Comment | |
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en14 |
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1xx55 | 2023-03-14 10:10:25 | 0 | (published) | |
en13 |
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1xx55 | 2023-03-14 10:04:56 | 1205 | (saved to drafts) | |
en12 |
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1xx55 | 2023-03-14 08:46:09 | 0 | (published) | |
en11 |
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1xx55 | 2023-03-14 08:45:53 | 31 | (saved to drafts) | |
en10 |
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1xx55 | 2023-03-14 08:37:00 | 0 | (published) | |
en9 |
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1xx55 | 2023-03-14 08:35:02 | 4 | Tiny change: ' , we can NOT use $k$ a' -> ' , we can **NOT** use $k$ a' | |
en8 |
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1xx55 | 2023-03-14 08:33:58 | 13 | Tiny change: 'nCode here:\n~~~~~\n#' -> 'nCode here (GNU C11)\n~~~~~\n#' | |
en7 |
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1xx55 | 2023-03-14 08:29:50 | 1155 | Tiny change: 'n\nCode:\n ' -> 'n\nCode:\n~~~~~\nincl\n~~~~~\n\n\n ' | |
en6 |
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1xx55 | 2023-03-14 08:16:01 | 135 | Tiny change: '} \equiv \left\{k_{X} & ' -> '} \equiv \{k_{X} & ' | |
en5 |
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1xx55 | 2023-03-14 07:59:14 | 337 | Tiny change: ' $r=$\left{ 01A=2A>20A=21A>2\begin{arr' -> ' $r=$\left\{ \begin{arr' | |
en4 |
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1xx55 | 2023-03-14 06:39:52 | 4 | Tiny change: ')+r \pmod m(A-1)$ , $0 \le' -> ')+r \pmod {m(A-1)}$ , $0 \le' | |
en3 |
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1xx55 | 2023-03-14 06:38:22 | 80 | Tiny change: ': we do $k% %+=% %r/(A-1)$ a' -> ': we do $k$ $+=$ $r/(A-1)$ a' | |
en2 |
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1xx55 | 2023-03-14 06:16:49 | 524 | Tiny change: '{i=0}A^{i} mod m$' -> '{i=0}A^{i}$ $ mod $ $m$' | |
en1 |
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1xx55 | 2023-03-14 05:56:14 | 94 | Initial revision (saved to drafts) |
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