The goal is to find $$$\sum^{X-1}_{i=0}A^{i} mod m$$$
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my solution of Atcoder Beginner Contest 293 E
The goal is to find $$$\sum^{X-1}_{i=0}A^{i} mod m$$$
Rev. | Lang. | By | When | Δ | Comment | |
---|---|---|---|---|---|---|
en14 | 1xx55 | 2023-03-14 10:10:25 | 0 | (published) | ||
en13 | 1xx55 | 2023-03-14 10:04:56 | 1205 | (saved to drafts) | ||
en12 | 1xx55 | 2023-03-14 08:46:09 | 0 | (published) | ||
en11 | 1xx55 | 2023-03-14 08:45:53 | 31 | (saved to drafts) | ||
en10 | 1xx55 | 2023-03-14 08:37:00 | 0 | (published) | ||
en9 | 1xx55 | 2023-03-14 08:35:02 | 4 | Tiny change: ' , we can NOT use $k$ a' -> ' , we can **NOT** use $k$ a' | ||
en8 | 1xx55 | 2023-03-14 08:33:58 | 13 | Tiny change: 'nCode here:\n~~~~~\n#' -> 'nCode here (GNU C11)\n~~~~~\n#' | ||
en7 | 1xx55 | 2023-03-14 08:29:50 | 1155 | Tiny change: 'n\nCode:\n ' -> 'n\nCode:\n~~~~~\nincl\n~~~~~\n\n\n ' | ||
en6 | 1xx55 | 2023-03-14 08:16:01 | 135 | Tiny change: '} \equiv \left\{k_{X} & ' -> '} \equiv \{k_{X} & ' | ||
en5 | 1xx55 | 2023-03-14 07:59:14 | 337 | Tiny change: ' $r=$\left{ 01A=2A>20A=21A>2\begin{arr' -> ' $r=$\left\{ \begin{arr' | ||
en4 | 1xx55 | 2023-03-14 06:39:52 | 4 | Tiny change: ')+r \pmod m(A-1)$ , $0 \le' -> ')+r \pmod {m(A-1)}$ , $0 \le' | ||
en3 | 1xx55 | 2023-03-14 06:38:22 | 80 | Tiny change: ': we do $k% %+=% %r/(A-1)$ a' -> ': we do $k$ $+=$ $r/(A-1)$ a' | ||
en2 | 1xx55 | 2023-03-14 06:16:49 | 524 | Tiny change: '{i=0}A^{i} mod m$' -> '{i=0}A^{i}$ $ mod $ $m$' | ||
en1 | 1xx55 | 2023-03-14 05:56:14 | 94 | Initial revision (saved to drafts) |
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