Today, I had spent hours trying to solve problem : (https://mirror.codeforces.com/contest/1334/problem/C) and submitted several solutions with an O(n) complexity, but I kept getting a TLE. After some further inspection, I changed from using cin to scanf, and my solution was finally accepted. While it's well-known that scanf is slightly faster than cin, I was surprised by how much of a difference it actually made in this case.
TLE Code : 284211972 Accepted Code : 284212724
This blog may not be overly educational, but I just want to highlight that even a O(n) solution can lead to a TLE error. Understanding this can help you avoid the frustration and wasted time that I experienced.
ios::sync_with_stdio(false);cin.tie(nullptr); cout.tie(nullptr);
Use this if you want to use cin/cout
what does
cout.tie(nullptr)do?explanation
cout = Output + cout.flush(). But if you use cout.tie(nullptr) it will untie the cin with cout. So cout = Output only. In interective problems if you don't use cout.tie(nullptr); you don't have to use flush manually as it will be done automatically.
Using this will help a lot with time complexity specially when you have multiple test cases.
And forgive my poor English
no, it's all about
cin.tie(nullptr);as far as i knowNothing because by default
coutis not tied to anything.I think cout is tied with cin. Everytime you use cin after a cout it flushes the output. Though I am not sure if cout.tie(nullptr) or cin.tie(nullptr); does the work of untie.
Actually, not. You can double check this, just print the result of
std::cout.tie(nullptr)(the method returns the current tied stream and if there is no tied stream, a null pointer is returned).Yeah, Got it.So, I am just using a line for no reason.I just need
cin.tie(nullptr);. Thanks.I thought everyone learns to put
cin.tie(0) -> sync_with_stdio(0)in their code the first day they start cp.Guess not :/
it does not affect complexity, QED.
std::cinis tied (or synchronized) withstd::coutby default in C++, which means it will ensure that yourstdoutwill always be flushed before the input operations. It makes your program slows due to the fact that you have to flush the output before you take the next input fromstdin. If you provide those:Then they are untied, and the output will only be flushed when
stdoutis full, or your program has been terminated. That's why you see the whole output after reading and processing all test cases. And that's why it is said that usingendlis not a good practice as it flush your output immediately, which means using those two lines of codes above are useless. This blog is quite nice and you should take a look.(I thought I have remind you before but you didn't really care about that).