Hi friends, on an average how many operations can be performed in 1 second,is it 10^7 or 10^9?
Hi friends, on an average how many operations can be performed in 1 second,is it 10^7 or 10^9?
| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | turmax | 3559 |
| 6 | tourist | 3541 |
| 7 | strapple | 3515 |
| 8 | ksun48 | 3461 |
| 9 | dXqwq | 3436 |
| 10 | Otomachi_Una | 3413 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 157 |
| 2 | adamant | 153 |
| 3 | Um_nik | 147 |
| 4 | Proof_by_QED | 146 |
| 5 | Dominater069 | 145 |
| 6 | errorgorn | 142 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | TheScrasse | 134 |
| 10 | chromate00 | 133 |
In codeforces it's something like 4 * 10^8 operations per second.
And for spoj and codechef?
You can check it by yourself — put a cycle which does some fixed number of operations in your solution for problem like A+B and look at running time of this solution at given OJ.
Obviously different operations are running with different speed — doing A+B isn't same as doing A%B.
You can try with this in C...
long long int a;
time_t start_time,end_time;
time(&start_time);
while(1)
{
a++;
time(&end_time);
if((end_time — start_time)==1) //for 1 second
{printf("%lld",a); break;}}