Given an unsorted sequence A={a0,a1,a2,......an-1} of n integers. How do I find the longest increasing sub-sequence of the given sequence. Is there any dynamic programming solution.
→ Обратите внимание
→ Лидеры (рейтинг)
| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3611 |
| 4 | jiangly | 3583 |
| 5 | strapple | 3515 |
| 6 | tourist | 3470 |
| 7 | dXqwq | 3436 |
| 8 | Radewoosh | 3415 |
| 9 | Otomachi_Una | 3413 |
| 10 | Um_nik | 3376 |
| Страны | Города | Организации | Всё → |
→ Лидеры (вклад)
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 163 |
| 2 | adamant | 150 |
| 3 | Um_nik | 146 |
| 4 | Dominater069 | 144 |
| 5 | errorgorn | 141 |
| 6 | cry | 139 |
| 7 | Proof_by_QED | 136 |
| 8 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 9 | TheScrasse | 134 |
→ Найти пользователя
→ Прямой эфир
Codeforces (c) Copyright 2010-2026 Михаил Мирзаянов
Соревнования по программированию 2.0
Время на сервере: 14.05.2026 12:46:19 (g2).
Десктопная версия, переключиться на мобильную.
При поддержке
Do you need this solution?
A[i] - our sequence
DP[i] = the length of the LIS ending with element numbered i.
We'll keep track of vector V as follows:
V[j] = A[k], such that dp[k] = j and k is the largest number < i, satisfying this condition.
Suppose, we have found out all the dp[1..i-1], and V is up to date. How to find dp[i]? It's easy to find by binary search on V, isn't it? OK, find it, and don't forget to update V.
Start with dp[1] = 1 and V[1] = A[1] (1-based sequence)
I mean that when saying "By sorting all values we had before and binary search on them?".
1) override elements in V and
2) append elements to V.
You can try to solve it here: http://acm.tju.edu.cn/toj/showp2400.html