| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3611 |
| 4 | jiangly | 3583 |
| 5 | strapple | 3515 |
| 6 | tourist | 3470 |
| 7 | Radewoosh | 3415 |
| 8 | Um_nik | 3376 |
| 9 | maroonrk | 3361 |
| 10 | XVIII | 3345 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 162 |
| 2 | adamant | 148 |
| 3 | Um_nik | 146 |
| 4 | Dominater069 | 143 |
| 5 | errorgorn | 141 |
| 6 | cry | 138 |
| 7 | Proof_by_QED | 136 |
| 8 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 10 | soullless | 133 |
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0
Rest in peace |
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0
For problem E, we can calculate every position, the first 0 to the right of every bit. Then for each query, iterate each bit from low to high, and check first 0 to the right. If the current bit of k is 1, it needs to satisfy all the smallest right end points that are not 0. If the current bit of k is 0, since we iterate from low to high, the rightmost non-0 can be greater than or equal to k. I am not sure if my solution is correct, after all, it has not passed the system test. But I want to share my ideas with you, and the code is as follows: https://mirror.codeforces.com/contest/1878/submission/225352692 |
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+3
Why is the C problem so TLE-constrained for python…… |
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0
It's a really good contest and let me return to violet, thanks to problems setter~ |
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0
Fully agree. I spent most of time to understanding what to do and then very little time to coding. |
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+13
Me too! |
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+8
Thanks so much for there're py solution~ |
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0
Sure enough, I got further away from purple。。 |
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0
There are so many submission still in queue, I'm really worried about getting stuck in the contest tonight. |
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+9
How far is purple? |
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+3
Finally I become red handle in this special timing. |
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0
According to the rating was rolled back, so I participate in this round will be rated or not? |
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0
Me too(^_^) |
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+1
And there is no editorial too |
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