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Thanks for that implementation. I now understood it But why are you not printing cout.flush() after printing the query? |
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I thought of a similar line but there's a problem with that. First, there can be multiple occurrences of y as well so we cannot simply write (n-2)! for the remaining. Secondly, there can be multiple occurrences of x as well and in that case, the answer will be n!. I tried handling these 2 cases but it became very complex. The editorial's approach is quite simpler than that. |
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thanks! this visualisation made it much more clearer |
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didn't knew about your channel earlier, will definitely follow for more such content |
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