→ Обратите внимание
→ Лидеры (рейтинг)
| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | turmax | 3559 |
| 6 | tourist | 3541 |
| 7 | strapple | 3515 |
| 8 | ksun48 | 3461 |
| 9 | dXqwq | 3436 |
| 10 | Otomachi_Una | 3413 |
| Страны | Города | Организации | Всё → |
→ Лидеры (вклад)
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 157 |
| 2 | adamant | 153 |
| 3 | Um_nik | 147 |
| 3 | Proof_by_QED | 147 |
| 5 | Dominater069 | 145 |
| 6 | errorgorn | 142 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | TheScrasse | 134 |
| 10 | chromate00 | 133 |
→ Найти пользователя
→ Прямой эфир
Комментарии
|
+7
Registration complete. Hope for the best of Athoy. |
|
0
Can anyone explain how to approach problem C? |
|
+13
Congratulations!! |
|
На
MikeMirzayanov →
Codeforces Round 606(Div.1, Div.2) and Technocup — Elimination Round 4, 6 лет назад
+1
Can anyone explain how to solve Div.2 D, please? |
|
-30
I hope to become specialist in this contest. :) |
|
0
Got it. Thank you. |
|
0
Choosing 5 twice is a solution, fine. But why choosing 7 and 3 isn't possible? |
|
0
Problem A: test case 2: 42 32 In the note it said that: you cannot choose p=7, subtract it, then choose p=3 and subtract it again. Can anyone explain why it's not possible? |
Codeforces (c) Copyright 2010-2026 Михаил Мирзаянов
Соревнования по программированию 2.0
Время на сервере: 17.04.2026 09:12:24 (g2).
Десктопная версия, переключиться на мобильную.
При поддержке
