| 2020 ICPC Asia East Continent Final |
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| Закончено |
Prof. Pang works for the City Brain program of Capital Grancel. The road network of Grancel can be represented by an undirected graph. Initially, the speed limit on each road is $$$1$$$m/s. Prof. Pang can increase the speed limit on a road by $$$1$$$m/s with the cost of $$$1$$$ dollar. Prof. Pang has $$$k$$$ dollars. He can spend any nonnegative integral amount of money on each road. If the speed limit on some road is $$$a$$$m/s, it takes $$$1/a$$$ seconds for anyone to go through the road in either direction.
After Prof. Pang spent his money, Prof. Du starts to travel from city $$$s_1$$$ to city $$$t_1$$$ and Prof. Wo starts to travel from city $$$s_2$$$ to city $$$t_2$$$. Help Prof. Pang to spend his money wisely to minimize the sum of minimum time of Prof. Du's travel and Prof. Wo's travel. It is guaranteed that $$$s_1$$$ and $$$t_1$$$ are connected by at least one path and that $$$s_2$$$ and $$$t_2$$$ are connected by at least one path.
The first line contains three integers $$$n$$$, $$$m$$$, $$$k$$$ ($$$1\le n \le 5000$$$, $$$0\le m \le 5000$$$, $$$0\le k\le 10^9$$$) separated by single spaces denoting the number of vertices, the number of edges in the graph and the number of dollars Prof. Pang has.
Each of the following $$$m$$$ lines contains two integers $$$a$$$, $$$b$$$ ($$$1\le a, b\le n, a\neq b$$$) separated by a single space denoting the two endpoints of one road. There can be multiple roads between the same pair of cities.
The following line contains four integers $$$s_1$$$, $$$t_1$$$, $$$s_2$$$, $$$t_2$$$ ($$$1\le s_1, t_1, s_2, t_2\le n$$$) separated by single spaces denoting the starting vertices and ending vertices of Prof. Du and Prof. Wo's travels.
Output one decimal in the only line – the minimum sum of Prof. Du's travel time and Prof. Wo's travel time. The answer will be considered correct if its absolute or relative error does not exceed $$$10^{-9}$$$.
6 5 1 1 2 3 2 2 4 4 5 4 6 1 5 3 6
5.000000000000
1 0 100 1 1 1 1
0.000000000000
4 2 3 1 2 3 4 1 2 3 4
0.833333333333
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