After learning the strange sorting algorithm in the problem Paimon Sorting of The 2021 ICPC Asia Nanjing Regional Contest, Little Cyan Fish comes up with the following task.
Given a sequence $$$a_1, a_2, \cdots, a_n$$$ which is a permutation of $$$n$$$, your task is to sort the permutation in ascending order by applying the following operation for at most $$$\lfloor \frac{n}{2} \rfloor$$$ times: Choose two indices $$$l$$$ and $$$r$$$ satisfying $$$1 \le l \lt r \le n$$$ and $$$a_l \gt a_r$$$, and then sort $$$a_l, a_{l + 1}, \cdots, a_r$$$ in ascending order.
Recall that a permutation of $$$n$$$ is a sequence of length $$$n$$$, in which each integer from $$$1$$$ to $$$n$$$ (both inclusive) appears exactly once. Also recall that $$$\lfloor x \rfloor$$$ indicates the largest integer less than or equal to $$$x$$$.
$$$^{\text{∗}}$$$Stanley P. Y. Fung. Is this the simplest (and most surprising) sorting algorithm ever? arXiv:2110.01111
There are multiple test cases. The first line of the input contains an integer $$$T$$$ indicating the number of test cases. For each test case:
The first line contains an integer $$$n$$$ ($$$1 \le n \le 100$$$) indicating the length of the permutation.
The second line contains $$$n$$$ distinct integers $$$a_1, a_2, \cdots, a_n$$$ ($$$1 \le a_i \le n$$$) indicating the given permutation.
It's guaranteed that the sum of $$$n$$$ of all test cases will not exceed $$$10^4$$$.
For each test case, first output one line containing one integer $$$k$$$ ($$$0 \le k \le \lfloor \frac{n}{2} \rfloor$$$) indicating the number of operations you're going to use. Then output $$$k$$$ lines, where the $$$i$$$-th line contains two integers $$$l_i$$$ and $$$r_i$$$ separated by a space, indicating the two indices you choose for the $$$i$$$-th operation.
It can be proven that the answer always exists. If there are multiple valid answers, you can output any of them.
362 3 4 6 5 151 2 3 4 532 3 1
2 3 6 1 3 0 1 1 3
For the first sample test case, after the $$$1$$$-st operation the permutation becomes $$$\{2, 3, 1, 4, 5, 6\}$$$, and after the $$$2$$$-nd operation the permutation becomes $$$\{1, 2, 3, 4, 5, 6\}$$$, which is in ascending order.
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