Suppose you are working in the Ministry of Digital Development of Berland, and your task is to monitor the industry of video blogging.
There are n bloggers in Berland. Recently, due to the poor state of the main video platform in Berland, two alternative platforms were introduced. That's why bloggers started to reupload their videos to these alternative platforms. You've got the statistics that the i-th blogger uploaded vi videos to the first alternative platform and ri videos to the second alternative platform.
You think that a potential user will be upset if even at least one of his favorite bloggers doesn't upload anything. However, if a blogger uploads videos to both platforms, the user will watch that blogger on the platform where more videos are available. So, you've come up with the following function to estimate user experience. Suppose a user watches k bloggers b1,b2,…,bk; then, let user experience be E(b1,…,bk)=max
In order to get some statistics, you want to calculate the value \mathit{avg}_k that is equal to an average experience among all subsets of bloggers of size k. Also, you have to calculate \mathit{avg}_k for each k from 1 to n.
Since answers may be too large, print them modulo 998\,244\,353.
The first line contains a single integer n (1 \le n \le 2 \cdot 10^5) — the number of bloggers.
The second line contains n integers v_1, v_2, \dots, v_n (0 \le v_i \le 10^6), where v_i is the number of videos of the i-th blogger on the first alternative platform.
The third line contains n integers r_1, r_2, \dots, r_n (0 \le r_i \le 10^6), where r_i is the number of videos of the i-th blogger on the second alternative platform.
Print n integers \mathit{avg}_1, \mathit{avg}_2, \dots, \mathit{avg}_n.
It can be proven that \mathit{avg}_k may be represented as an irreducible fraction \dfrac{x}{y} where y \not\equiv 0 \pmod{998\,244\,353}. So, print \mathit{avg}_k in a form x \cdot y^{-1} \bmod 998\,244\,353.
32 1 21 2 1
2 332748119 1
45 5 5 50 0 0 0
5 5 5 5
51 9 3 7 52 4 6 8 5
6 4 3 199648873 2
In the first example, 332748119 is \frac{4}{3}. In the third example, 199648873 is \frac{12}{5}.