This is the easy version of the problem. The difference between the versions is that in this version, $$$n \leq 700$$$. You can hack only if you solved all versions of this problem.
Legend has it that when Gauss was a young schoolboy, his teacher tasked the class with summing the integers from $$$1$$$ to $$$100$$$, likely as a way to keep them occupied for a while. However, young Gauss quickly came up with the formula $$$\text{sum} = \frac{n(n+1)}{2}$$$ and found the answer in mere moments. Centuries later, Gauss appears before you in a nightmare with a daunting task...
You are given a positive integer $$$n$$$, find a sequence of integers $$$[a_1, a_2, \ldots, a_n]$$$ such that $$$1 \leq a_i \leq 10^{18}$$$ for all $$$1 \leq i \leq n$$$, and the GCDs of pairwise adjacent elements of $$$a$$$ are all distinct. Formally,
Additionally, $$$a$$$ should have the minimum possible number of distinct elements.
Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 200$$$). The description of the test cases follows.
The first and only line of each test case contains a single integer $$$n$$$ ($$$2 \leq n \leq 700$$$) — the size of the sequence to be found.
For each test case, output $$$n$$$ space-separated positive integers $$$a_1, a_2, \ldots, a_n$$$ ($$$1 \leq a_i \leq 10^{18}$$$) on a new line that satisfy the condition in the statement. If there are multiple solutions, print any of them.
It can be proven that under the problem constraints, a solution always exists.
3257
2 2 1 4 4 6 6 4 4 6 6 9 9 4
For the second test case, the GCDs of adjacent elements are $$$[\gcd(1, 4), \gcd(4, 4), \gcd(4, 6), \gcd(6, 6)] = [1, 4, 2, 6]$$$, all of which are distinct.
For the third test case, the GCDs of adjacent elements are $$$[\gcd(4, 4), \gcd(4, 6), \gcd(6, 6), \gcd(6, 9), \gcd(9, 9), \gcd(9, 4)] = [4, 2, 6, 3, 9, 1]$$$, all of which are distinct.
For each test case, it can be proven that no sequence with fewer distinct elements exists such that all adjacent GCDs are distinct.