You have a prize wheel divided into $$$l$$$ sections, numbered from $$$0$$$ to $$$l-1$$$. The sections are arranged in a circle, so after section $$$l-1$$$, the numbering continues again from section $$$0$$$.
Initially, the prize pointer is at section $$$a$$$. Each time you spin the wheel, the pointer moves exactly $$$b$$$ sections forward. That is, after one spin, the pointer moves from section $$$a$$$ to section $$$(a+b)\bmod l$$$, after two spins to $$$(a+2b)\bmod l$$$, and so on$$$^{\text{∗}}$$$.
You may spin the wheel any number of times (including zero). After you stop, the section where the pointer finally lands determines your prize: you receive an amount equal to the number of that section.
What is the maximum prize you can obtain?
$$$^{\text{∗}}$$$Here, $$$x \bmod y$$$ denotes the remainder from dividing $$$x$$$ by $$$y$$$.
Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 500$$$). The description of the test cases follows.
The first line of each test case contains three integers $$$l, a$$$, and $$$b$$$ ($$$1 \le l, b \le 5000$$$, $$$0 \le a \le l-1$$$).
For each test case, output the maximum prize that can be obtained.
45 3 22 0 68 2 4100 0 1
40699
In the first test case, by spinning the wheel three times and then claiming the reward, you can obtain a maximum value of $$$4$$$. The sequence of pointer positions is: $$$3, 0, 2, 4, 1, 3, 0, \ldots$$$
In the second test case, the pointer will remain on section $$$0$$$ indefinitely.
In the fourth test case, with $$$b = 1$$$ and starting from section $$$0$$$, the pointer will iterate over all sections, including the last one.
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