binary search blog

Revision en25, by Semyazi, 2025-12-06 02:15:33

Introduction

Binary search is one of those algorithms that's easy to understand the idea of, but often hard to work out the implementation details. For example, should it be $$$\text{lo}=0$$$ or $$$\text{lo}=1$$$? Should I set $$$\text{lo}$$$ to $$$\text{mid}$$$ or $$$\text{mid}+1$$$? Is the answer going to be $$$\text{lo}$$$ or $$$\text{hi}$$$? The questions are endless. Today, I'd like to share with you a perspective I discovered that made it easier for me to implement binary search. It makes the implementation much simpler as you will hardly even have the opportunity to make off-by-one errors. I hope you find it helpful!

Motivating Problem

Suppose you're given an array $$$\text{A}$$$ of $$$0$$$s and $$$1$$$s indexed from $$$1$$$ to $$$n$$$. Additionally, you know:

  • $$$A[1] = 0$$$
  • $$$A[n] = 1$$$

Your goal is to find consecutive indices $$$\ell$$$ and $$$r$$$ so that:

  • $$$1\leq\ell \lt r\leq n$$$
  • $$$A[\ell]=0$$$
  • $$$A[r]=1$$$

Of course you could loop $$$\ell$$$ from $$$1$$$ to $$$n-1$$$ and compare it with $$$\ell+1$$$, but $$$10^9$$$ operations is quite slow.

Logarithmic solution
Implementation

Generalizing Using Predicates

I hope you agree that the implementation to the above solution was very clean and essentially wrote itself once you understand the idea. Wouldn't it be nice if every binary search problem could be solved just like this? It turns out that we can do that! The above problem is the quintessential binary search problem. At its very core, binary search is not related to sorted arrays at all.

To generalize this, we have to define a concept called a predicate. A real predicate in math is something abstract, but for us, a predicate is a function from a contiguous sequence of integers $$$\{\ell,\ell+1,\dots,r\}$$$ (where $$$\ell \lt r$$$) to $$$\{0,1\}$$$. Essentially, it allows us to create an array of $0$s and $1$s as in the motivating problem.

Predicate Example

To see an example of how all of this comes together, we'll solve the problem of finding the index of a value in a sorted array; this is the usual problem that motivates binary search. Formally, you're given a sorted integer array $$$A$$$ indexed from $$$1$$$ to $$$n$$$ and an integer $$$v$$$. Your goal is to find the first (i.e. smallest) index of $$$A$$$ where $$$v$$$ occurs.

To set this problem up, we'll define the predicate $$$P$$$ on $$$\{1,2,\dots,n\}$$$ as follows:

Generalized Binary Search

Tags binary search, intermediate, advanced

History

 
 
 
 
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en97 English Semyazi 2026-01-16 01:38:19 0 (published)
en96 English Semyazi 2026-01-16 01:37:43 3
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en33 English Semyazi 2025-12-06 03:28:26 26
en32 English Semyazi 2025-12-06 03:27:44 2 Tiny change: ';\n }\n \n // o' -> ';\n }\n \n // o'
en31 English Semyazi 2025-12-06 03:26:56 895
en30 English Semyazi 2025-12-06 03:21:25 297 Tiny change: 'predicate. So, we ca' -> 'predicate.\n\n$\bigoplus$\n\n So, we ca'
en29 English Semyazi 2025-12-06 03:15:10 1072
en28 English Semyazi 2025-12-06 03:00:52 47 Tiny change: '\dots,n\\} and speci' -> '\dots,n\\}$ and speci'
en27 English Semyazi 2025-12-06 02:59:29 966
en26 English Semyazi 2025-12-06 02:16:43 0 Tiny change: 'ray of $0$s and $1$s as in th' -> 'ray of $0$ s and $1$ s as in th'
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en21 English Semyazi 2025-11-21 03:13:17 244 Tiny change: '\nint r = 1e9;\n\nwhile' -> '\nint r = n;\n\nwhile'
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en13 English Semyazi 2025-11-21 02:57:43 6 Tiny change: 'te slow.\n' -> 'te slow.\naeou\n'
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en10 English Semyazi 2025-11-21 02:51:58 1 Tiny change: 'at:\n\n- $\1\leq\ell<' -> 'at:\n\n- $1\leq\ell<'
en9 English Semyazi 2025-11-21 02:51:48 2 Tiny change: 'so that:\n- $\1\le' -> 'so that:\n\n- $\1\le'
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en5 English Semyazi 2025-11-20 15:27:31 178 Tiny change: 'xt{A}$ of 0s and 1s' -> 'xt{A}$ of $0$s and 1s indexed from $1$'
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en1 English Semyazi 2025-11-20 15:12:42 22 Initial revision (saved to drafts)