what happens when you take the XOR of whole array with an element
what to do in the case when the XOR of the array is zero
Compute the XOR of the whole array, what happen when the XOR of the whole array is ZERO the ans is YES.
If the XOR is not zero then from which number we should XOR that it becames zero
If XOR is X the X^a[i]=0 then X=a[i] because removing the element for the array is same as XORing it again, then if X(XOR of the whole array) is present in the array then we can remove it and then make the XOR zero else the ans is NO
675587B - The magical operation
If a element doesn't divide x now will it ever divide it again.
if it divides x now and get multiplied with y at max how many times it will get updated (Remember then the element will never exceed 1e18 limit)
what about the case in which y==1
lets assume thier is a magical x which is divisible by every number then how many times a single element will get updated if y>1 -- at max 60.
when y==1 then just skip the operation because it will not updated any number.
what about when y is not zero and also and element is not updated because x%a[i]!=0. If when x%a[i]!=0 then will it ever be divisible after any update.. No
lets assume two number X and Y if X%Y==0 then every factor of Y will also divides X but if a factor of Y doesn't divides X then will Y also not divide X. If a is not a factor of X then a*b will also be not the factor of X.
so now we can save all the indx which divides x and remove them when they will no longer divides x
to remove indx from x is o(n) if a[i] divides x then o(32*n)(x is <=2e9) if y>1 if y==1 skip the operation as the distinct unique value of x is <= 500 it will work.
675587C - Ashutosh and his dreams
think from the back
now when you add x can you know what value it will get converted to at the end.
The trick lies in processing the queries in reverse.Think about it: an element added at query $$$i$$$ is only affected by Type 2 operations that occur after query $$$i$$$. If we know what a value $$$v$$$ "eventually becomes" by the end of all queries, we can immediately determine the final value of any number we append.
Create an array (let's call it parent or f) where f[v] represents what the value $$$v$$$ currently transforms into. Initially, f[v] = v for all $$$v$$$ up to the maximum possible value ($$$3 \cdot 10^5$$$).
Start from the $$$q$$$-th query and work back to the 1st.
Process Type 2 ($$$2, x, y$$$): In reverse, this operation means that any $$$x$$$ existing before this point will eventually be treated as $$$x + y$$$.Update the mapping: f[x] = f[x + y].
Process Type 1 ($$$1, x$$$):When we "add" $$$x$$$ (in reverse, this is the moment the element was born), its final value is whatever f[x] is at that moment.Store f[x] in a result list.
Since we processed Type 1 queries from last to first, reverse your result list and print it.
this the question of invariance
multiply the x and the y coordinate
if you see for x that the toggles happens in pair (x,x,x+1,x+1) the xor of the x coordinate will never change
If you multiply the x and the y coordinate then



