Hello everyone,↵
I wrote down a problem statement in class because I was bored. Sadly, I didn't figure out its solution.↵
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Problem: ↵
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Walid was assigned to build a network, however the required network is unique in it's own sense.↵
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The assigned network consists of 2 types of nodes: Group Owners and Slaves.↵
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Each group consists of a group owner and at most d slaves.↵
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Note: You can't have a group inside a group.↵
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Each second, r nodes will join the network. There will be a total of m insertions.↵
A node can either declare itself as a group owner, or join an existing network if possible.↵
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However,creating a GO costsfor a node to declare itself as a group owner, there will be an overhead of weighcost d, while joining an existing network costs an overhead of weight 1.↵
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At time 0, the network is empty.↵
Walid task is to createthea network with minimum weight possibleoverhead.↵
↵
Input:↵
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- n0 : Initial number of nodes-↵
- m : Number of insertions↵
- r : Number of nodes joining the network↵
- d : Maximum number of slaves allowed per group↵
↵
Output:↵
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Print theinitial number of groups requiredat t = 1 to build a network with least cost at time m.↵
↵
↵
I think this problem is a DP problem.↵
Any help?↵
Thanks!
I wrote down a problem statement in class because I was bored. Sadly, I didn't figure out its solution.↵
↵
Problem: ↵
Walid was assigned to build a network, however the required network is unique in it's own sense.↵
↵
The assigned network consists of 2 types of nodes: Group Owners and Slaves.↵
↵
Each group consists of a group owner and at most d slaves.↵
↵
Note: You can't have a group inside a group.↵
↵
Each second, r nodes will join the network. There will be a total of m insertions.↵
A node can either declare itself as a group owner, or join an existing network if possible.↵
↵
However,
↵
At time 0, the network is empty.↵
Walid task is to create
↵
Input:↵
-----
- n0 : Initial number of nodes
- m : Number of insertions↵
- r : Number of nodes joining the network↵
- d : Maximum number of slaves allowed per group↵
↵
Output:↵
-------↵
Print the
↵
Any help?↵
Thanks!
