can you please why this code is having run time error???
this problem is from today's contest ....
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | cry | 166 |
2 | maomao90 | 163 |
2 | Um_nik | 163 |
4 | atcoder_official | 161 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 157 |
8 | TheScrasse | 154 |
9 | nor | 153 |
9 | Dominater069 | 153 |
can you please why this code is having run time error???
this problem is from today's contest ....
Can anyone provide me a good source to learn about minimum spanning tree in a directed graph.The sources I found in the internet were very complex...
My c++ solution got accepted. But same process for java causing memory limit exceeded error. can any one explain ??? it's a segment tree problem . I am just switching my language from cpp to java. but i am facing problem while submitting in different on line judges. As in this case same code in c++ got accepted.
Any tips to solve problem in java will definitely help me. I am in great danger.
my code
import java.util.*;
class segmnetTree {
int [] array, segarray; segmnet() { array=new int[100001]; segarray=new int[400001]; } int left(int n) { return 2*n; } int right( int n) { return 2*n+1; } void brmq(int p, int l, int r) { if(l==r) { segarray[p]=array[l]; return; } brmq(left(p),l,(l+r)/2); brmq(right(p),(l+r)/2+1,r); segarray[p]=Math.min(segarray[left(p)],segarray[right(p)]); } int rmq( int p,int l, int r, int i, int j) { if(i>r || j<l) return -1; // MAXXXX or set it in a way to understand else if(l>=i && r<=j) return segarray[p]; int a1=rmq( left(p), l,(l+r)/2, i,j); int a2=rmq( right(p), (l+r)/2+1 , r , i,j); if(a1==-1) return a2; if(a2==-1) return a1; else return Math.min(a1,a2); }
}
public class SegmentTree {
public static void main(String[] args) { segmnet s1=new segmnet(); Scanner sin=new Scanner(System.in); int cas=sin.nextInt(); for( int cno=1; cno<=cas;cno++) { int n,q; n=sin.nextInt(); q=sin.nextInt(); for( int m=1;m<=n;m++) { s1.array[m]=sin.nextInt(); } s1.brmq(1,1,n); System.out.println("Case "+cno+":"); for( int m=0;m<q;m++) { int i,j; i=sin.nextInt(); j=sin.nextInt(); System.out.println(s1.rmq(1,1,n,i,j)); } } }
}
Name |
---|