Given an array of integers A of length N. For each index i, find number of indices j(j!=i) such that gcd(A[i],A[j])>1.
Constraints:
N<=1e5
1<=A[i]<=N
Example:
A = [4,3,2,4] output = [2,0,2,2]
A = [2,3,6,4,6,5] output = [3,2,4,3,4,0]
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | strapple | 3515 |
| 6 | tourist | 3470 |
| 7 | dXqwq | 3436 |
| 8 | Radewoosh | 3415 |
| 9 | Otomachi_Una | 3413 |
| 10 | Um_nik | 3376 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | adamant | 152 |
| 3 | Proof_by_QED | 146 |
| 3 | Um_nik | 146 |
| 5 | Dominater069 | 144 |
| 6 | errorgorn | 141 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 9 | TheScrasse | 134 |
Given an array of integers A of length N. For each index i, find number of indices j(j!=i) such that gcd(A[i],A[j])>1.
Constraints:
N<=1e5
1<=A[i]<=N
Example:
A = [4,3,2,4] output = [2,0,2,2]
A = [2,3,6,4,6,5] output = [3,2,4,3,4,0]
Hello Codeforces!
I have a doubt in today contest problem A :(https://mirror.codeforces.com/contest/1557/problem/A)
I submitted solution in which I have used accumulate function to get sum of all elements of vector but it gave me WA.
And finally I got AC in which I find sum by traversing all elements.
Is there any difference in both methods to get sum of all elements of vector?
Here are the links of my both submissions :
125393659 — WA
125396830 — AC
Please help me to find out the error in code(using accumulate function).
Thanks in advance:)
UPD : Resolved
| Name |
|---|


