| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | tourist | 3985 |
| 2 | jiangly | 3885 |
| 3 | jqdai0815 | 3682 |
| 4 | Benq | 3580 |
| 5 | orzdevinwang | 3526 |
| 6 | ksun48 | 3506 |
| 7 | ecnerwala | 3505 |
| 8 | Radewoosh | 3457 |
| 9 | Kevin114514 | 3377 |
| 10 | gamegame | 3374 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | cry | 170 |
| 2 | Um_nik | 162 |
| 3 | atcoder_official | 161 |
| 4 | maomao90 | 158 |
| 4 | -is-this-fft- | 158 |
| 6 | djm03178 | 157 |
| 7 | Dominater069 | 156 |
| 8 | adamant | 154 |
| 9 | luogu_official | 153 |
| 10 | awoo | 152 |
While solving 1612C - Chat Ban I found something weird. I have submitted same code with C++14 and C++17,C++20. But it only was accepted with C++17.
C++14 :158761775
C++17 :158762654
C++20 :158762172
I tried to look for the reason online but could not find any.
contact your local exorcist asap
https://mirror.codeforces.com/contest/1612/submission/158779409
compare your solution with this modified solution of yours you will get it
or simply k*(k+1)/2 is not equal to (k*(k+1))/2
so in your code k*(k+1)/2 will give correct result if $$$k$$$ is $$$odd$$$ else it will give one less value then expected
i tried this code in custom test and it gives the correct result even if k is even.
I don`t think it`s the reason because the order of operator is defined in the standard of c++.
i think it is because of precision issues, i fixed it by adding (long double) inside the sqrt function: 158781091
yaa you are right