erniepsycholone's blog

By erniepsycholone, 2 years ago, In English

1933A - Turtle Puzzle: Rearrange and Negate

Idea: snowysecret, prepared: snowysecret

Tutorial
Solution

1933B - Turtle Math: Fast Three Task

Idea: snowysecret, prepared: snowysecret, erniepsycholone

Tutorial
Solution

1933C - Turtle Fingers: Count the Values of k

Idea: dbsbs, prepared: dbsbs, snowysecret

Tutorial
Solution

1933D - Turtle Tenacity: Continual Mods

Idea: snowysecret, erniepsycholone, prepared: snowysecret

Tutorial
Solution

1933E - Turtle vs. Rabbit Race: Optimal Trainings

Idea: snowysecret, prepared: snowysecret

Tutorial
Solution

1933F - Turtle Mission: Robot and the Earthquake

Idea: erniepsycholone, prepared: erniepsycholone

Hint
Tutorial
Solution

1933G - Turtle Magic: Royal Turtle Shell Pattern

Idea: snowysecret, jerryliuhkg, prepared: snowysecret

Tutorial
Solution

Hope the contest was in some way helpful in improving your skills, and that you all had fun!

“If you only do what you can do, you will never be more than you are now.” – Master Oogway

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2 years ago, hide # |
 
Vote: I like it +6 Vote: I do not like it

This Round was really amazing. I really enjoyed this round. The problems are very good.

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2 years ago, hide # |
 
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For the problem F tutorial (spoiler alert): I don't understand this part: "Finally, choose the best among all n tiles after waiting for the endpoint to cycle back." can someone explain it to me?

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    2 years ago, hide # ^ |
     
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    Let $$$b_i$$$ be the minimum time needed to reach cell $$$(i, m-2)$$$ in the transformed problem. Then, it takes $$$b_i + 1$$$ time to reach cell $$$(i, m-1)$$$ in the transformed problem.

    The transformation we did is to imagine the robot moving down instead of the rocks moving up. Therefore in reality it takes $$$b_i + 1$$$ time to reach cell $$$(c_i, m-1)$$$ where $$$c_i = (i-(b_i+1)) \bmod n$$$. Hence, to reach $$$(n-1, m-1)$$$ we really need $$$b_i + 1 + \min(c_i + 1, n - 1 - c_i)$$$ time.

    Therefore the answer is just $$$\min_{i=0}^{n-1} b_i + 1 + \min(c_i + 1, n - 1 - c_i)$$$ where $$$b$$$ and $$$c$$$ arrays are defined above.

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      2 years ago, hide # ^ |
       
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      I have seen solution for same problem via simple bfs to reach to end position how come that solution works scratching my head on that for a while

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2 years ago, hide # |
 
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For F,I dont understand why the row update 3 times like"for(int j=0;j<3*n;j++)".I try using 2 times and get WA,3 times AC.HOW?

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    2 years ago, hide # ^ |
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    As RT can go from $$$(x,y)$$$ to $$$((x+2) \text{ mod } n,y)$$$, if x=0 currently, and $$$n \text{ mod } 2=1$$$, it would require the 2 times you mentioned. However, if $$$x!=0$$$, we need to loop $$$3$$$ times to run an entire cycle throughout a column. An example would be if RT is at $$$(3,0)$$$, with $$$n=5$$$, the following operations would be needed to run through column $$$0$$$:

    $$$(3,0)$$$ --> $$$(0,0)$$$ --> $$$(2,0)$$$ --> $$$(4,0)$$$ --> $$$(1,0)$$$ --> $$$(3,0)$$$

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      2 years ago, hide # ^ |
       
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      Hello,I still don't understand.I used"for(int i=0;i<200*n;i++)for(int j=0;j<m;j++)" and WA on test 36. Why we should run m before n?my submission

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      22 months ago, hide # ^ |
       
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      Hi, but why should it complete a cycle? like in 2 loops it is able to reach till (1,0), why should it get back to (3,0)? (my assumption is that the optimal path to reach is starting at (3,0) so going a loop back to (3,0) seems redundant)

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2 years ago, hide # |
 
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Thank you for the great round!) I've finally got the pupil)

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2 years ago, hide # |
 
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I tried to solve problem E using ternary search but it gave TLE on 8th test case (https://mirror.codeforces.com/contest/1933/submission/249501917), can anyone share the ternary search solution for problem E.

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2 years ago, hide # |
 
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In E, they used the following formula to calculate the first t terms of an arithmetic series: ~~~~~ int ut = (u + (u — t + 1)) * t / 2; ~~~~~ But it is wrong because u-t+1 might be negative, and in that case, the standard formula doesn't work, but why does it pass the test cases?

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9 months ago, hide # |
 
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Love the Master Oogway quote.

He would be proud

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4 months ago, hide # |
 
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Interesting problems! Specially 1933D - Turtle Tenacity: Continual Mods