Noobish_Monk's blog

How to efficiently count specific regular bracket sequences?
By Noobish_Monk, history, 8 months ago, In English

I came up on a problem and got it to solving this one, but now I am stuck. Can someone help please?

How can we efficiently count the number of regular bracket sequences with length $$$2n$$$ that have first closing bracket on position $$$k + 1$$$ (any way faster than $$$O(nk)$$$ or $$$O(n^2))$$$?

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8 months ago, # |
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In this blog(https://mirror.codeforces.com/blog/entry/87585) you can find number of bracket sequences with lenght 2n with a prefix on k open brackets. I belive(if i didnt missunderstand)your problem reduces to the number with a prefix of k minus the number with a prefix of k+1.(The first k will be open and the k+1th will be closed)

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8 months ago, # |
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Isn't this similar to the CSES problem: https://cses.fi/problemset/task/2187 ?

But with the input:

$$$ 2\cdot n\\ \underbrace{(((...(}_{k\ \text{times}}) $$$
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8 months ago, # |
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if the first closing bracket is on $$$k + 1$$$, then first $$$k$$$ brackets are opening right?

if so, just solve cses bracket sequences II with $$$s_1 = s_2 = ... s_k = ($$$ and $$$s_{k+1} = )$$$

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