There are N points and M segments, the ith point is located at p[i] and the ith segment's size is s[i]. What is the maximum number of points that can be covered by these segments?
My current solution is O(N * 2^M * M). Is there any better solution?
There are N points and M segments, the ith point is located at p[i] and the ith segment's size is s[i]. What is the maximum number of points that can be covered by these segments?
My current solution is O(N * 2^M * M). Is there any better solution?
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Auto comment: topic has been updated by lcha (previous revision, new revision, compare).
Auto comment: topic has been updated by lcha (previous revision, new revision, compare).
can you provide the link to the problem
No. I'm preparing some problems for our company contest and I came up with this problem.
I think you solution is something like this:
Let's sort points, then do this DP:
$$$dp(i, msk) =$$$ Maximum number of points $$$\leq p_i$$$, where $$$msk$$$ is a bitmask of used segments.
$$$dp(i, msk) = min(dp(i-1, msk), dp(lowerbound(i-sz_j), msk \oplus 2^j))$$$
yes, something like that