you have an array in one operation choose two different element and remove from array return minimum length of array
you can do this operation any number of times
you have an array in one operation choose two different element and remove from array return minimum length of array
you can do this operation any number of times
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Use greedy and don't use dp because why not
Store the count of all elements using a map.
If there is an element whose count x>floor(n/2) then answer is x-(n-x);
Else answer is 0 if n is even and 1 if n is odd.
(n=size of the array)
Thanks
Glad to help. Ask me if you don't understand my solution.