Hi everyone , i'm trying to solve SPOJ POLQUERY from COCI 2006 (Croatian Olympiad in Informatics) but i don't understand oficial solutions. Can somebody explain me ideas in order to solve this challenger problem.
Thanks in Advance.
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3611 |
| 4 | jiangly | 3583 |
| 5 | strapple | 3515 |
| 6 | tourist | 3470 |
| 7 | Radewoosh | 3415 |
| 8 | Um_nik | 3376 |
| 9 | maroonrk | 3361 |
| 10 | XVIII | 3345 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 162 |
| 2 | adamant | 148 |
| 3 | Um_nik | 146 |
| 4 | Dominater069 | 143 |
| 5 | errorgorn | 141 |
| 6 | cry | 138 |
| 7 | Proof_by_QED | 136 |
| 8 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 10 | soullless | 133 |
Hi everyone , i'm trying to solve SPOJ POLQUERY from COCI 2006 (Croatian Olympiad in Informatics) but i don't understand oficial solutions. Can somebody explain me ideas in order to solve this challenger problem.
Thanks in Advance.
| Name |
|---|



If a road connecting G1 and G2 disconnects two vertices A and B, that means the number of connected components has increased. By definition, this means the road is a bridge.
What may not be obvious is the inverse: if G1-G2 is a bridge, this means that if any path from A to B goes through G1-G2, then all paths from A to B use the G1-G2 road. In other words, a necessary and sufficient condition for the path to be blocked is that G1-G2 is a bridge and is used in at least one path from A-B. So the algorithm is simply:
It's still not clear how to find the paths. The trick is to consider only a spanning tree of the graph (the DFS tree, for example). In that case there is only a single path between any pair of vertices, and it's easy to check if G1-G2 belongs to it.
Query 2 is very similar.
Very nice idea and explanation , i don't really know that property about bridges.
Thanks.
How was "very similar" did you mean?
ffao I could not develop a similar claim for articulation vertices in query2. Could you please explain it in some detail ?
I am very weak in this area so I may be wrong. Please feel free to point out any mistakes.
For articulation vertices, they split the graph into biconnected components. If you create a graph of biconnected components as well as articulation vertices, it will look like a tree. Then you can find out, first if the deleted node is an articulation vertex, AND if path from bi-component of A to bi-component of B in this tree passes through the deleted node. If both are true then A is disconnected from B.
L.
I am using the idea that you told but I get WA on 10th test case.