Prequisites
This proof uses the following 3 facts:
$$$1.\quad -\frac{a}{b}=\frac{a}{-b}$$$
$$$2.\quad -0=0$$$
$$$3.\quad x=x$$$ is always true.
The Proof
Let $$$e$$$ be assigned the fraction $$$\frac{n}{0}$$$ for clarity.
Lemma: $$$e=-e$$$
Proof of Lemma:
$$$e=-e$$$
$$$\frac{n}{0}=-(\frac{n}{0})$$$
Move the $$$-$$$ in the denominator.
$$$\frac{n}{0}=\frac{n}{-0}$$$
And $$$-0=0$$$ so:
$$$\frac{n}{0}=\frac{n}{0}$$$
Hence $$$e=-e$$$
If $$$e=-e$$$ then:
$$$2e=0$$$
$$$e=0$$$
Thus, $$$\frac{n}{0}$$$ is $$$0$$$ for all $$$n$$$.
I would like to know about any mistakes in the comments. (Except for the fact that $$$\frac{n}{0}$$$ is illegal)








Pretty interesting proof, and obviously, except for the fact that we can prove anything with this:
$$$2 = 3$$$
$$$ \frac{2}{0} = \frac{3}{0}$$$
$$$0 = 0$$$
Ohh, well, I guess that has a crucial flaw!
We can multiply both sides of any equation by $$$0$$$, which allows us to prove or disprove anything this way. Thus, we cannot use this reasoning to give a counterargument against the so-called proof.
Interesting... I think n/0 is illegal for a reason.
I think all you proved was
X = -X then X = 0
Any mistakes?
e/e = 1
(n/0)/(n/0) = 1
0/0 = 1
suppose x = 0
x/0 = 1
0 = 1
Proof by contradiction
SO I guess n/0 will stay illegal or we'll have to invent new math.
why is e/e=1? to derive this you must be multilpying/dividing the equation by 0.
$$$-\frac{a}{b}=\frac{a}{-b}$$$ is true only when $$$b\ne 0$$$.
anything divided by 0 is not defined. but you have equated n/0 to -(n/0) how can you equate something that is not defined
I said "mistakes in the comments. (Except for the fact that n/0 is illegal)" and this was just for fun no actual defining n/0.
Although this might seem bogus, I respect how in-depth this is and how you actually used real mathematics equalities and didn't make up anything(other than ignoring n/0 is undefined)! You earned yourself an upvote.