atcoder_official's blog

By atcoder_official, history, 5 months ago, In English

We will hold AtCoder Beginner Contest 433.

We are looking forward to your participation!

  • Vote: I like it
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5 months ago, hide # |
 
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hope this time D will be easier than E:)

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“THE SEG OF E”

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Rev. 2  
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To all Coder's who do more on atcoder rather than CF,

What are topics roughly seen in each rating range (Brown, Green, Cyan, Blue, ....)

maspy PCTprobability hirayuu_cf sheyasutaka physics0523

and all other(these people I know but they don't know me.)

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Everyone will AK this contest,this contest is very easy.(That is my hope)

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Hope the contest is easy.

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Oh,This contest are easy than ABC431.

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AK!!

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《容易》

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This round is easy.

I have also AK it.

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Can we stop having heavy-implementaion problems on short-duration contests plz?

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Very good contest!
However i noticed that problem D is quite similar to this problem, 1029D - Concatenated Multiples

And also how to solve F?

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But how do you think of that many people just copied G's original problem‘s solution? I don't think allow people to do so is fair.

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Again we have a stupid E and a super standard G.

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In fact, I really hope AtCoder official should ban people from copying solutions. If not, I'll probably not even dare to take part in ABC!

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Can someone explain me how to solve D in a clear and in more dpth?

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Video solution of D. 183183 in detailed explanation — https://youtu.be/m2UAKskunpA

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Nowadays, almost every AtCoder Beginner Contest has original problems or very classic ones. Could it be that there are no new problems left to create?

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Oh!I only add 8 rating

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For problem G, I used DFS to traverse the DAG of the SAM, but why did it TLE and MLE??? That prevented me from AK this contest...

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Loved problem F

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Can anyone help me, what is my program missing in problem E.

https://atcoder.jp/contests/abc433/submissions/71178772

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Does anyone understand why you don't have to subtract $$$C_{m}^{n + 1}$$$ from $$$C_{n+m}^{n+1}$$$ while $$$n \leq m$$$? If you use the way of two sets in the editorial, you will have to subtract that :(