We will hold AtCoder Beginner Contest 433.
- Contest URL: https://atcoder.jp/contests/abc433
- Start Time: http://www.timeanddate.com/worldclock/fixedtime.html?iso=20251122T2100&p1=248
- Duration: 100 minutes
- Writer: sounansya
- Tester: MMNMM, kyopro_friends
- Rated range: ~ 1999
- The point values: 100-200-300-400-450-500-600
We are looking forward to your participation!








hope this time D will be easier than E:)
Last time, I got stuck on D for so long that I didn’t even get to attempt E, but after the contest I solved E in just 10 minutes.
orz
I spend 10min for D but 50 for unsolved E and found F looks ez
“THE SEG OF E”
Can anyone help me, what is my program missing in problem E. I am going in ascending order, I think this should be possible.
https://atcoder.jp/contests/abc433/submissions/71178772
To all Coder's who do more on atcoder rather than CF,
What are topics roughly seen in each rating range (Brown, Green, Cyan, Blue, ....)
maspy PCTprobability hirayuu_cf sheyasutaka physics0523
and all other(these people I know but they don't know me.)
Everyone will AK this contest,this contest is very easy.(That is my hope)
Maybe.
I hope too.
Hope the contest is easy.
Hope so.
IT'S EASY!
(I'm excluded because I'm a newbie, but at least I solve A,B,C and D)
Me too
You are a newbie, so what am I? I only solved A,B,C and wrote D,E wrongly.(I am a Chinese junior high school student, so please don't blame me if there are any grammatical errors)Luckily, there is no penalty time on AtCoder.(Might be sounding a bit formal here
I'm still a Chinese pupil... (and write E,F,G in a wrong way...)
%%%(I am a pupil too)
me too
My 2nd ABC, and I'd solved ABCDF. I don't know how they AK so fast.
My At name is the same as Codeforces.
r u in coderlands too? (i mean yangzichen1203)
wow i just solve A,B,C,D (I'm 'Mouse1234Abc' on Atcoder)
yes
Oh,This contest are easy than ABC431.
AK!!
Wow
stO Orz
《容易》
Don't comment in Chinese!!!
pls don't comment in Chinese because if people who didn't know Chinese will confused about your comment (those people:Hey what's this???)
Oh,sorry.
Never speak Chinese at Codeforces please.
This round is easy.
I have also AK it.
orz I can only solve A,B,C,D ORZ ORZ ORZ
Can we stop having heavy-implementaion problems on short-duration contests plz?
Very good contest!
However i noticed that problem D is quite similar to this problem, 1029D - Concatenated Multiples
And also how to solve F?
Treat every digit in the array as T/2-th digit or T/2+1-th digit and use prefix and suffix array to check the options before and after it.
what is the formula for calculating options
nCr(leftOptions+rightOptions,leftOptions+1)
But how do you think of that many people just copied G's original problem‘s solution? I don't think allow people to do so is fair.
Again we have a stupid E and a super standard G.
how E?
Rank each cell in the matrix by the maximal element it permits (the minimum of the two corresponding maximums).
Thanks.
In fact, I really hope AtCoder official should ban people from copying solutions. If not, I'll probably not even dare to take part in ABC!
Can someone explain me how to solve D in a clear and in more dpth?
you can try this, may be — https://youtu.be/m2UAKskunpA
Video solution of D. 183183 in detailed explanation — https://youtu.be/m2UAKskunpA
Nowadays, almost every AtCoder Beginner Contest has original problems or very classic ones. Could it be that there are no new problems left to create?
Fun Fact: Problem D in CodeForces
The contest is from 7 years ago. How do you guys remember?
I failed to solve a problem that I have already solved before...
I didn't expect this to be 1900 rated
Oh!I only add 8 rating
For problem G, I used DFS to traverse the DAG of the SAM, but why did it TLE and MLE??? That prevented me from AK this contest...
Loved problem F
Me too.But I don`t accepted it.
Want to train together?
Can anyone help me, what is my program missing in problem E.
https://atcoder.jp/contests/abc433/submissions/71178772
Does anyone understand why you don't have to subtract $$$C_{m}^{n + 1}$$$ from $$$C_{n+m}^{n+1}$$$ while $$$n \leq m$$$? If you use the way of two sets in the editorial, you will have to subtract that :(