Блог пользователя patience

Автор patience, 10 лет назад, По-английски

http://mirror.codeforces.com/contest/127/problem/C i have solved this problem. solution :http://mirror.codeforces.com/contest/127/submission/11415525

in my solution code..i find y1 and y2 as follows code;

for(i64 i=0;i<=x2;i++)
  {
     y2=i;
     y1=min(y2*(t2-t0)/(t0-t1),x1);
   //  if(i==99)cout<<y2<<" "<<ans<<" "<<ans_x<<" "<<ans_y<<endl;
     if(y1+y2==0)continue;
     if(((t1*y1+t2*y2)*(ans_x+ans_y))<(ans*(y1+y2)) || ((((t1*y1+t2*y2)*(ans_x+ans_y))==(ans*(y1+y2))) && (y1+y2)>(ans_x+ans_y)))
     {
         ans=t1*y1+t2*y2;
         ans_x=y1;
         ans_y=y2;
     }
  }

it gives correct output..

i also find y1 and y2 another way..but it does not gives correct output..

for(i64 i=0;i<=x1;i++)
  {
     y1=i;
     y2=min(y1*(t1-t0)/(t0-t2),x2);
   //  if(i==99)cout<<y2<<" "<<ans<<" "<<ans_x<<" "<<ans_y<<endl;
     if(y1+y2==0)continue;
     if(((t1*y1+t2*y2)*(ans_x+ans_y))<(ans*(y1+y2)) || ((((t1*y1+t2*y2)*(ans_x+ans_y))==(ans*(y1+y2))) && (y1+y2)>(ans_x+ans_y)))
     {
         ans=t1*y1+t2*y2;
         ans_x=y1;
         ans_y=y2;
     }
  }

where is my wrong in second procedure

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