Can anybody plz ezplain:
for(int i = 1; i <= n; i++) { scanf("%s", a[i] + 1); }
I know this one
for(int i = 1; i <= n; i++) { scanf("%s", a[i] ); }
But I don't know the use of above scanf("%s", a[i] + 1); Plz guide me on this.
# | User | Rating |
---|---|---|
1 | tourist | 3803 |
2 | jiangly | 3707 |
3 | Benq | 3627 |
4 | ecnerwala | 3584 |
5 | orzdevinwang | 3573 |
6 | Geothermal | 3569 |
6 | cnnfls_csy | 3569 |
8 | Radewoosh | 3542 |
9 | jqdai0815 | 3532 |
10 | gyh20 | 3447 |
# | User | Contrib. |
---|---|---|
1 | awoo | 163 |
1 | maomao90 | 163 |
3 | adamant | 161 |
4 | maroonrk | 152 |
5 | -is-this-fft- | 151 |
6 | nor | 150 |
7 | atcoder_official | 147 |
7 | SecondThread | 147 |
9 | TheScrasse | 146 |
10 | Petr | 145 |
Can anybody plz ezplain:
for(int i = 1; i <= n; i++) { scanf("%s", a[i] + 1); }
I know this one
for(int i = 1; i <= n; i++) { scanf("%s", a[i] ); }
But I don't know the use of above scanf("%s", a[i] + 1); Plz guide me on this.
Name |
---|
When you use scanf() you must give a pointer to it. When you use scanf("%d", a[i]+1) it means that you are using 1-based indexing, So the your string is starting from index 1(not 0).
Can I do the same with strings, what I mean is:
string st; cin >> (st + 1);
I know it is does not work but is there any way to do this?
you can do:
string st;
cin >> st;
st = ((string)" ") + st;
Thanks
Can u tell after I perform certain operations, now I want to print original string without initial space given at beginning. What I would do then?
st.erese (st.begin ())