Can somebody please explain, why in the following question,
http://mirror.codeforces.com/problemset/problem/576/A are we checking with all the powers of a prime whether the given number is divisible or not? why don't we stop, for a prime factor, as soon as we find its first power that is either greater than n or doesn't divide it completely ?
→ Pay attention
→ Streams
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | tourist | 3985 |
| 2 | jiangly | 3814 |
| 3 | jqdai0815 | 3682 |
| 4 | Benq | 3529 |
| 5 | orzdevinwang | 3526 |
| 6 | ksun48 | 3517 |
| 7 | Radewoosh | 3410 |
| 8 | hos.lyric | 3399 |
| 9 | ecnerwala | 3392 |
| 9 | Um_nik | 3392 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 169 |
| 2 | maomao90 | 162 |
| 2 | Um_nik | 162 |
| 4 | atcoder_official | 161 |
| 5 | djm03178 | 158 |
| 6 | -is-this-fft- | 157 |
| 7 | adamant | 155 |
| 8 | awoo | 154 |
| 8 | Dominater069 | 154 |
| 10 | luogu_official | 150 |
→ Find user
→ Recent actions
Codeforces (c) Copyright 2010-2024 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Dec/23/2024 01:37:48 (k1).
Desktop version, switch to mobile version.
Supported by
we are printing all prime powers that are less then or equal to N, we dont stop if the prime powers does not divide N completely, but we do stop if the prime powers are greater then N,
for example: if N is 25, and vasya's number is 24
if we stop if a given prime power does not divide n completely, when checking powers of 2, we would stop immedietly (because 2 does not divide 25), and it would be impossible to determine the number