fcspartakm's blog

Editorial Technocup 2017 — Elimination Round 1
By fcspartakm, history, 8 years ago, translation, In English
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8 years ago, # |
  Vote: I like it +5 Vote: I do not like it

First of all, I didn't even come to know when this editorial came.
In D, there was the constraint "Each person needs S or M, M or L, L or XL" and so on.
I was wondering how to solve D if this constraint is removed. I was trying to maintain what all people are left with just a SINGLE choice, so I have no option but to give them the t-shirt of their choice, and on doing so, find new people that are left with single choice.
Ofcourse, this can stop mid-way, and we would be left with people having exactly two choices. But I couldn't analyse how to proceed ahead. My failed attempt

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    8 years ago, # ^ |
    ← Rev. 2   Vote: I like it 0 Vote: I do not like it

    You can just build a network and run max flow on it and it will pass since the graph is special.

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      8 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      That's cool. Then I guess this problem from last contest is also basically the same but with cost assigned to each edge.(MinCostMaxFLow) I am new to the concept of max flow, but let me know whether I am thinking correct or not. Also can you share some AC codes on CF/CC where you used MaxFlow and MinCostMaxFlow because I am not able to find a good template for them.

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        8 years ago, # ^ |
          Vote: I like it +3 Vote: I do not like it

        Try this.My solution 17710740.

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          8 years ago, # ^ |
            Vote: I like it 0 Vote: I do not like it

          Your implementation is not the fastest right? So instead of adjacency matrix, i should implement it with vectors and that would be the best code in terms of time complexity?

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      8 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      Can you please explain what do u mean by the graph is special and how will it pass using max flow algorithms?

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

How to solve Problem E using rolling Hash for strings.

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