Hello CodeForces Community!
Being your Secret Santa this Christmas, I have packed a nice little gift for you. I am happy to invite you to the ACM-ICPC Asia — Kharagpur Onsite Mirror Contest ACM-ICPC Asia — Kharagpur Onsite Mirror Contest. Please do come and open your little gift on 17th December 1000 hours IST.
Joining me on the problem setting panel are:
Problem Testers: Errichto(Kamil Debowski), kingofnumbers(Hasan Jaddouh), kevinsogo(Kevin Charles Atienza)
Problem Setters: PraveenDhinwa(Praveen Dhinwa), Balajiganapathi(Balajiganapathi Senthilnathan), animeshf(Animesh Fatehpuria), arjunarul(Arjun Arul), adurysk(Surya Kiran), kevinsogo(Kevin Charles Atienza).
I hope you will enjoy solving them. Please give your feedback on the problem set in the comments below after the contest. You can find the rest of the details about the contest below.
Time: 17th December 2016 (1000 hrs) to 17th December 2016 (1500 hrs). (Indian Standard Time — +5:30 GMT) — Check your timezone.
Details: https://www.codechef.com/KGP16MOS
Registration: You just need to register as a Team on CodeChef. Those who are interested and do not have a CodeChef handle are requested to register in order to participate.
Good Luck! Hope to see you participating!
update: Onsite round delayed by 90 minutes, due to delay in Onsite contest.
Is there a public ranklist for the onsite?
You can see the live updates from codechef here
Onsite Mirror has started!
Hi will you please publish any editorial of the problems? ? ( Of course after the contest ) Thanks in advance.
Where is the final rank list?
Also, if possible, please move the problems into practise.
Here it is -> Link
https://www.codechef.com/KGP16MOS/problems/KGP16A How to solve this one? Name of the problem is "Finding seats"
IS the answer for sweet shop in kolkata always one or two??
Yes, I think so..Though I did not participate in the contest So I am not sure but I think when s = q or s = n-q then answer is 1 otherwise 2.
is it like when it is two u should ossicilate between odd and even numbers do you have same idea or any other??
Yes something like k k+2 ... n n-1 n-3....