I tried this problem using segment tree but it's getting TLE. Can anybody explain how to remove TLE from this code?
Solution : https://pastebin.com/8iuk4mQp
Problem : http://www.spoj.com/problems/PATULJCI/
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3611 |
| 4 | jiangly | 3583 |
| 5 | strapple | 3515 |
| 6 | tourist | 3470 |
| 7 | dXqwq | 3436 |
| 8 | Radewoosh | 3415 |
| 9 | Otomachi_Una | 3413 |
| 10 | Um_nik | 3376 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 161 |
| 2 | adamant | 149 |
| 3 | Um_nik | 146 |
| 4 | Dominater069 | 143 |
| 5 | errorgorn | 141 |
| 6 | cry | 138 |
| 7 | Proof_by_QED | 135 |
| 7 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 10 | TheScrasse | 133 |
I tried this problem using segment tree but it's getting TLE. Can anybody explain how to remove TLE from this code?
Solution : https://pastebin.com/8iuk4mQp
Problem : http://www.spoj.com/problems/PATULJCI/
| Name |
|---|



Well, i don't see why this code should pass. There are simple alternatives than trying to squeeze a heavy-constant segment tree anyway, but if you still want to, you can read. I was able to pass with a Merge Sort Tree in szkopul using some constant optimization, code here. There is a simple solution using the fact that the element appears > 1/2 in the range, we can try to pick random a number between [L,R] and see if in the range, this number appears more than 1/2 times using a histogram, the probability of error is
if you try k numbers
I read that editorial but still couldn't get past the TLE. By the way that codechef question got AC. Thanks for help
Can you explain the probability idea more clearly as I am not aware about it
Just random generate index between L and R ~30 times and see if the number this index represent appears more than 1/2 in subarray [L,R]
Thanks for the idea