The tag says "DP"
I have tried many DP forms
DP[i][j] = true if S[i, j] is a wraparound string`` TLE
DP[i] = # of substrign ending at index i``` --> Can't find recurrence because of distinct condition.
Any help?
# | User | Rating |
---|---|---|
1 | tourist | 3985 |
2 | jiangly | 3814 |
3 | jqdai0815 | 3682 |
4 | Benq | 3529 |
5 | orzdevinwang | 3526 |
6 | ksun48 | 3517 |
7 | Radewoosh | 3410 |
8 | hos.lyric | 3399 |
9 | ecnerwala | 3392 |
9 | Um_nik | 3392 |
# | User | Contrib. |
---|---|---|
1 | cry | 169 |
2 | maomao90 | 162 |
2 | Um_nik | 162 |
4 | atcoder_official | 161 |
5 | djm03178 | 158 |
6 | -is-this-fft- | 157 |
7 | adamant | 155 |
8 | awoo | 154 |
8 | Dominater069 | 154 |
10 | luogu_official | 150 |
The tag says "DP"
I have tried many DP forms
DP[i][j] = true if S[i, j] is a wraparound string`` TLE
DP[i] = # of substrign ending at index i``` --> Can't find recurrence because of distinct condition.
Any help?
Name |
---|
Seems pretty straightforward. For every character c , store the maximum length of a "good" substring ending at c. Answer would be the sum over all the characters , O(N) time and O(1) space.
Something like this should work.
Ah dammit, you finding this "straightforward," is pretty dis-heartening. I'm kind of disappointed I couldn't come up with this.
How do you come up with solutions like this? Ie, how did you think of this?
I dont know how to answer this. This just comes from practice i guess.