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Probability theory
Автор gilcu3, 12 лет назад, По-английски

I'm looking for a good source with deep theory and practice problems about probability, doesn't matter if it is too math involved, and I would prefer one that is ACM-ICPC training oriented.... thanks in advance..

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12 лет назад, # |
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I need help too!! Anyone? Also need help on game theory.

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12 лет назад, # |
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http://community.topcoder.com/tc?module=Static&d1=tutorials&d2=probabilities

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    12 лет назад, # ^ |
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    I've read that topcoder article already, but it doesn't seem to be enough, at least for solving problems where you must deal with expectations on random variables...

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12 лет назад, # |
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What would be necessary to learn to solve this problem? http://www.codechef.com/ACMAMR12/problems/MINMAX

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    12 лет назад, # ^ |
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    Nothing special , it just requires the basic definition of expected number and some about polynomial addition,multiplication and integration .

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      12 лет назад, # ^ |
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      How do you get the polynomials? I was able to doing only with two variables, by integrating over areas, but for more variables I didn't know what to do.

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        12 лет назад, # ^ |
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        I will try to explain my solution (though it seems more complex after I see others' solution.) Suppose you have to find the expected value of an expression ,say
        M = Max(x1,x2)
        Then ,from the definition we have
        Assume M = x , then we have to find the probability that value of M is x.
        This will be when one of x1 OR x2 is equal to x , and the other has a value less than x. So

        Hence , E[X] = 2 / 3 .This was the case of simple two variables.

        Now come to the general case , we want the probability of the operator at the root , such that value after that is x .
        Consider this as a state F(node , {either 0,1,2}) , here 0 means that we have to find probability such that it has value equal to x , 1 means to find less than x , 2 means to find greater than x . Now our answer is (root,0) .
        The transition for example is like :
        Suppose expression is : MmxxMxx , then at the root we have Maximum(a,b) operator and we want prob for being equal ,so answer will be:

        (F(root->left,0)*F(root->right,1) + F(root->left,1)*F(root->right,0)) . Here F(node,{0,1,2}) will be a polynomial.

        This is because either left value will be equal to x or right , and in either cases the other one will have value less than x.

        For base case , if we have a leaf and we have to calculate F(leaf,0) then it is 1 , for F(leaf,1) it is x , for F(leaf,2) it is (1-x) .

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