# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 157 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
Name |
---|
This can help you,
https://mirror.codeforces.com/blog/entry/65555?#comment-495656
Can you please explain the logic how to store dp[x][y].I am unable to understand the logic mentioned in the above link comment section.
You can apply the knapsack type DP approach to fill the table. The main logic For finding DP[x][i] you can take j = 1 to i values from current DP and take remaining (i-j) values from it's child DP and update current DP.