kabeer27's blog

[Suggestion] Point distribution for Easy/Hard version of problems
By kabeer27, history, 6 years ago, In English

In the recent contest and many other contests, the easy version of the problem is brute-force able its usually not much beneficial to solve the hard part first when you can brute force easy version to get more points and also like in https://mirror.codeforces.com/contest/1185

G1 was very easily doable by a brute force solution which I sadly didn't notice and it carried 2750 points.

I suggest that it should be the other way round, easy version should carry lesser points compared to the hard version, 750/2750 would have been a better option.

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6 years ago, # |
  Vote: I like it +13 Vote: I do not like it

True!

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6 years ago, # |
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Is this IOI?

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6 years ago, # |
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if you had solve just G1 in round #568, you will post this? (your opinion is all because of your failure).

sorry for poor english.

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6 years ago, # |
← Rev. 2   Vote: I like it +29 Vote: I do not like it

In my honest opinion, the ‘easy and hard version of a problem’ paradigm has no place in a scoring format like Codeforces. Prove me wrong.

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    6 years ago, # ^ |
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    Proof is obvious, thus it's left as an exercise for the reader.

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6 years ago, # |
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There is something else I noticed and I could be wrong but when you split a task into subtasks, over time, that tasks's points fall off twice as fast as in a regular problem, because there's one task made into two, and both of those lose points at the same rate as other problems.

So I see a lot of people in Div2 #568 where they solved ABC (C1 and C2) and are ranked lower than those who fast solved AB and C1. If this contest was AB and whole C, those that solved ABC1C2 would have 1750 (its never 1750 but just making a point) more points than those who solved AB but couldn't solve C2, which is a big difference.

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    6 years ago, # ^ |
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    Isn't this basically why people are having issues with keeping harder part with less points?

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