Here is the statement of problem B from the most recent contest (#571) for those who missed it. 571 — B
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What was the test case 3? I did (a+1) (b+1) /6.
If I'm not mistaken it likely was
4 4
or something like that.Your code would correctly produce
4
for that.However the expected answer according to the problem author's code would have been
3
which is clearly wrong as the following arrangement exists :Hi sir Can you please explain how you achieved that formula? Thank you.
In every 2x3 you can put one . so how many 2x3 blocks we have in our grid?
Thank you for the reply sir. perhaps I am not understanding correctly, but maximum you can put in a 2x3 is actually 2, and when you have an perfect number of 2x3s your can actually fit more (example is 4x6).
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