vovuh's blog

By vovuh, history, 5 years ago, translation, In English

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Hello! Codeforces Round 582 (Div. 3) will start at Aug/30/2019 17:35 (Moscow time). You will be offered 6 or 7 problems (or 8) with expected difficulties to compose an interesting competition for participants with ratings up to 1600. However, all of you who wish to take part and have rating 1600 or higher, can register for the round unofficially.

The round will be hosted by rules of educational rounds (extended ACM-ICPC). Thus, during the round, solutions will be judged on preliminary tests, and after the round it will be a 12-hour phase of open hacks. I tried to make strong tests — just like you will be upset if many solutions fail after the contest is over.

You will be given 6 or 7 (or 8) problems and 2 hours to solve them.

Note that the penalty for the wrong submission in this round (and the following Div. 3 rounds) is 10 minutes.

Remember that only the trusted participants of the third division will be included in the official standings table. As it is written by link, this is a compulsory measure for combating unsporting behavior. To qualify as a trusted participants of the third division, you must:

  • take part in at least two rated rounds (and solve at least one problem in each of them),
  • do not have a point of 1900 or higher in the rating.

Regardless of whether you are a trusted participant of the third division or not, if your rating is less than 1600, then the round will be rated for you.

Thanks to MikeMirzayanov for the platform, help with ideas for problems and for coordination of my work. Thanks to my good friends Mikhail awoo Piklyaev, Maksim Neon Mescheryakov and Ivan BledDest Androsov for help in round preparation and testing the round.

Good luck!

I also would like to say that participants who will submit wrong solutions on purpose and hack them afterwards (example) will not be shown in the hacking leaders table.

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UPD: Thanks to Artem Rox Plotkin for testing the round!

UPD2: Editorial is published!

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5 years ago, # |
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[deleted]

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5 years ago, # |
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I hope I will get some positive rating from the contest.

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    5 years ago, # ^ |
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    YOU WILL NOT!!!!!!!!!!!!!!! I AM SURE THAT AFTER 5 CONTESTS YOUR RAITING WILL BE BELOW 750!!!!!!!!!!!!!!!!!!!!!1

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      5 years ago, # ^ |
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      Why are you being mean?

      You are not even blue yet LMAO

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        5 years ago, # ^ |
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        In my real account my raiting is 1700+

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          5 years ago, # ^ |
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          No one cares..

          Just learn to be nice to people

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            5 years ago, # ^ |
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            I am just trolling in all my comments(not in posts).my small contribution can proof this. But this comment is not trolling and is true

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First,div3 after becoming expert hope my rating remains constant.

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    5 years ago, # ^ |
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    your rating will remain constant because div.3 is unrated to experts and higher like you and me.

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    5 years ago, # ^ |
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    Raiting does not matter, matter only nice girls!

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Now I can say "I won't lose my rating ANYWAY!" proudly :D

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    5 years ago, # ^ |
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    Now I can say "I won't gain any rating ANYWAY" sadly :(

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This will be my first contest. I hope I will do well and good luck for everyone for the same....

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5 years ago, # |
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Hope the ranking of problems be better from the last contest.

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After this contest,I think I will be a expert.How excited I am!

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Vovuh...master of preparing div3 contests...

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My Final exam is going on... But I won't miss div-3.. Div-3 is love..

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5 years ago, # |
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Vovuh's rounds are always good!

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Div 3 rounds are better than "Educational rounds" in teaching the most valuable skill for Codeforces, namely SPEED.

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    5 years ago, # ^ |
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    Depending upon what your purpose. If you have high rating is seem not :)) But I like Div3 rounds too :3

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Hopefully I will become back to expert soon. I have been very disappointing in myself recently.

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First unrated contest for me. XD

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Hello,Guys. This is my first contest after a lot of time. I studied Quantic Math in this period. I think that I can beat majority of the Div3 contestants even tough I am at 1361. :)

Letsssssss GOOOOOOOOOOOOOOOOOOOOOOOO

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    5 years ago, # ^ |
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    LoOooOoOLoOOooOoLoOOoOoOOooOooOOLoOooOOoOOoOOL. ROFL. LMAO. You think majority of contestants can only solve less than 3 problems?

    ↑that's just bullshit

    All the best. The time I solved 5 problems I didn't really expected that. it was pure luck. one lucky contest will be enough to bring you up to specialist or even 1500+. Good luck and have fun! :)

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Note that this is vovuh's round. It's likely to have problems with multiple queries. So guys, a notice for you, remember to clear the data of the last query before answering the queries!

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Do I have to register to join this contest? (My current rating is under 1600)

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    5 years ago, # ^ |
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    Of course. You have to register if you want to take part in a contest. For those rating equal or more than $$$1600$$$, they will be registered "Out of competition" for Div.3 contests. That is, their rating will remain unchanged after the round and they won't be listed in the official standing board.

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      5 years ago, # ^ |
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      Alright, thanks for the information

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    5 years ago, # ^ |
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    Yep

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I have a great idea! Make div3 rated for (blues,) purples and yellows but update ratings only if the delta is negative.

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    5 years ago, # ^ |
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    Why don't do the same thing to blues? They are unofficial for div.3 as well :(

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      5 years ago, # ^ |
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      sorry, I thought blues are also div3.

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Let's escape this division guys! :D

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Finally, not a Mathforces Round.

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P.S Here was bad info

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D2 solution accepted with 1900ms

Me: heavy breathing for 14 hours

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Unofficial editorial by me.

A (Chips Moving)

Explanation
Code

B (Bad Prices)

Explanation
Code

C (Book Reading)

Explanation
Code

D (Equalizing by Division)

Explanation
Code

E (Two Small Strings)

Explanation
Code

F (Unstable String Sort)

Explanation (grindy)
Code (grindy)
Explanation (nice)
Code (nice)

G (Path Queries)

Explanation
Code
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    5 years ago, # ^ |
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    Is this official editorial? I am confused why its not part of the post.

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    5 years ago, # ^ |
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    Your implementation of G has failed on a test in which function find makes $$$O(n)$$$ recursive steps. I believe it would be better to use rank heuristics here.

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thanks Vovuh, it was cool contest.

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Hopefully I go back to blue after open hacking is done!

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How does my D2 pass in time ? 59740108.

Isnt the complexity O(2*10^5 * K * log(K) ) while iterating the map since maximum numbers in map can be 2*10^5.

Am I missing something or are the test cases weak ?

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    5 years ago, # ^ |
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    Heh. I'm TLEing when I really shouldn't be.

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    5 years ago, # ^ |
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    No, your complexity analysis is wrong. The total number of elements across vectors in the map is at max Nlog(a[i]). So, you can say that your amortized time complexity is O(Nloga[i]logN)

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Can anyone tell me why this Java solution for D2 is TLEing?: 59748534

Shouldn't my solution be NlogN?

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In B i accidently took array smaller than the limits so i tried to hack myself and i can't hack it can anyone help me?

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    5 years ago, # ^ |
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    Difficult to hack, only hackable if those memory locations are assigned next to OS memory locations. Keep trying :P

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Can anyone tell me why my problem G TLE? I think it is O(N + M) (assuming that dsu operation is constant). Is there any infinite loop possibility?

59762107

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    5 years ago, # ^ |
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    return (pr[x] == x ? x : root(pr[x]));

    this line needs to be

    return (pr[x] == x ? x : pr[x] = root(pr[x]));

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      5 years ago, # ^ |
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      omg :( silly me

      Im actually used to code it like this

      return pr[x] = (pr[x] == x ? x : root(pr[x]));
      

      thank you XD, i think im just too tired right now..

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 Sad for him :(((( be hacked 4 problems :<<

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    5 years ago, # ^ |
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    Will those hack tests be included in final tests? What if my code fails in one or more of them?

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      5 years ago, # ^ |
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      Yes, if you not pass all test, you will be hack. =)))))))))

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      5 years ago, # ^ |
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      He is trolling lol. if your code fails in one of them, you get WA!

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Problem E :

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Solution for F

if d occurs at i position in a and j position in b then it can be said that
s[min(i,j)]=s[min(i,j)+1]=.......s[max(i,j)] make an array of intervals and add every [i,j] in it
sort the array
now merge the intervals which share common index
if length of the interval array is less than k then it is NO
else
if length of the interval is greater than 26 then merge all intervals from 26th index

assign letters from a to each interval
now sort intervals on the basis of their position in A.done AC

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5 years ago, # |
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Why the following brute force solution for D1 gives WA in test 5. https://mirror.codeforces.com/contest/1213/submission/59764056. Can someone have a look.

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русский Я очень люблю раунды vovuh. Спасибо! 1213E - Two Small Strings удивительно.

Ελληνικά Μου αρέσουν πολύ οι γύροι vovuh. Ευχαριστώ! 1213E - Two Small Strings είναι εκπληκτικό.

English I really like the rounds vovuh. Thanks! 1213E - Two Small Strings is amazing.

Español Realmente me gustan las rondas vovuh. ¡Gracias! 1213E - Two Small Strings es asombroso.

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This summer vacation I'v joined lots of cf's contests. before the new term , I wish I could be an 'expert'.