In a weighted tree, how to find for some node (u) the distance to another node (v) (answering Q queries effeiciently)? Constraints N <=10^3, Queries <=10^3
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | turmax | 3559 |
| 6 | tourist | 3541 |
| 7 | strapple | 3515 |
| 8 | ksun48 | 3461 |
| 9 | dXqwq | 3436 |
| 10 | Otomachi_Una | 3413 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 157 |
| 2 | adamant | 153 |
| 3 | Um_nik | 147 |
| 4 | Proof_by_QED | 146 |
| 5 | Dominater069 | 145 |
| 6 | errorgorn | 142 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | TheScrasse | 134 |
| 10 | chromate00 | 133 |
In a weighted tree, how to find for some node (u) the distance to another node (v) (answering Q queries effeiciently)? Constraints N <=10^3, Queries <=10^3
| Name |
|---|



Since N is small you can apply BFS starting from u in each query and print the distance of node v which will take O(n) time for each query. An efficient way to answer each query in O(logn) is using LCA which can be found in O(logn) using binary lifting.
I teach all these concepts with practice problems , here is the graph theory playlist where you can find this concept along with other concepts. https://www.youtube.com/playlist?list=PL2q4fbVm1Ik64I3VqbVGRfl_OgYzvzt9m hope this helps.