SHARECHAT 3RD QUESTION: A-Z COUNT
Need help on this question. I used map and binary search still all test cases not passed. Test is over now.
So if anybody can share the working code it would be helpful for me.\
Image:
# | User | Rating |
---|---|---|
1 | tourist | 3993 |
2 | jiangly | 3743 |
3 | orzdevinwang | 3707 |
4 | Radewoosh | 3627 |
5 | jqdai0815 | 3620 |
6 | Benq | 3564 |
7 | Kevin114514 | 3443 |
8 | ksun48 | 3434 |
9 | Rewinding | 3397 |
10 | Um_nik | 3396 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 156 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
10 | nor | 152 |
SHARECHAT 3RD QUESTION: A-Z COUNT
Need help on this question. I used map and binary search still all test cases not passed. Test is over now.
So if anybody can share the working code it would be helpful for me.\
Image:
Name |
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Just make vector for every character and find lower bound of k for S type queries and (lower bound of (k+1)) — 1 for L type queries. Also, Handle Not found condition. If you did the same and still getting WA to check your implementation.