Remind you that round will start in half an hour. The first thousand passes on. Link U can discuss tasks here after the end of the round, Good Luck!
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 157 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
Name |
---|
World chart showing
1000 * #Remaining / #Qualification_round
taken from Google CodeJam statistics page.Chart with
#Remaining
only (colors are not the best)Can anyone tell me whats wrong with my code for problem A which passes the small input, but not the large one? My idea is, that I count for every position the number of substring which could end at this position and sum them all up in the end...
Maybe accumulate is the problem:
vector<int> v(m);
return accumulate(v.begin(),v.end(),0);
will returnint
instead oflong long
template <class InputIterator, class T>
T accumulate ( InputIterator first, InputIterator last, T init );
accumulate(v.begin(),v.end(),0**LL**);
Thank you, got it!
why the analysis for 1B round hasn't been published yet?