A pattern can be seen in the solution that the result will be equal to (n/2)*m . May be I am missing any mathematical concept behind this reason. Can anyone provide me the mathematical logic behind the solution? Why is this working?
# | User | Rating |
---|---|---|
1 | tourist | 3993 |
2 | jiangly | 3743 |
3 | orzdevinwang | 3707 |
4 | Radewoosh | 3627 |
5 | jqdai0815 | 3620 |
6 | Benq | 3564 |
7 | Kevin114514 | 3443 |
8 | ksun48 | 3434 |
9 | Rewinding | 3397 |
10 | Um_nik | 3396 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 156 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
10 | nor | 152 |
A pattern can be seen in the solution that the result will be equal to (n/2)*m . May be I am missing any mathematical concept behind this reason. Can anyone provide me the mathematical logic behind the solution? Why is this working?
Name |
---|
lets take an example for n=12 and m=3.
So 1,2,3,7,8,9 will have -ve sign and 4,5,6,10,11,12 will have positive sign
Now if you look carefully you can see that a n/2 pairs consisting of one +ve and one -ve numbers are formed such that their addition is equal to m
here,
4 — 1 = 3
5 — 2 = 3
6 — 3 = 3
10 — 7 = 3
11 — 8 = 3
12 — 9 = 3
Therefore n/2 pairs will be formed having sum of both numbers as m. Hence the answer is (n/2)*m
Why am i getting Runtime Error when using Fast IO but AC without that! WA AC