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You are given two arrays a and b each of size n. For each i (0<=i<n), you have to find smallest 'x' such that
-> x+y = a[i]
-> x^y = b[i] (i.e. x xor y = b[i])
0<=a[i],b[i]<=10^(15)
1<=n<=50
It is possible that there might be no 'x' possible. Would be glad if anyone could help...
It is possible
By x^y do you mean power or the bitwise operator?
Use this property :- (x + y) = (x ^ y) + 2*(x & y)