tmwilliamlin168's blog

My CP Course "Zero to Hero" is now open for pre-registration!
By tmwilliamlin168, history, 4 years ago, In English

Having had a ton of experience with CP, I have decided that I could share my knowledge the best with the world by making a course! This course currently has lessons designed for people of many levels, from newbies to low masters.

Currently, I have opened pre-registration. I'm currently just trying to get an idea of how many people would be interested in such a course (and also to catch possible bugs on the website).

Here is the course website: http://course.williamlin.io/

100 lucky winners who pre-register will be given beta access to the course for free! Pre-registration won't be open for long though, so be sure to do it quick!

Update:

Thanks to every who pre-registered! The pre-registration assessment proved to be tough, and we decided to offer spots for beta access even for those who did not pass the test! Look out for an email from course@williamlin.io for your decision letter, as well as solutions and more opportunities to gain beta access to the course!

Update 2:

Congrats to the people who were selected to be part of the beta course:

Spoiler

Here are the solutions:

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  • Vote: I like it
  • +254
  • Vote: I do not like it

Comments Comments (72)
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4 years ago, # |
← Rev. 2   Vote: I like it +293 Vote: I do not like it

Happy April fool's to you too!

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4 years ago, # |
  Vote: I like it +238 Vote: I do not like it

Oops... No offense but seems like you lack a bit of practice...

Solutions to this pre-registration test will be released soon.

Come back again once you have learned the fundamentals!

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    4 years ago, # ^ |
      Vote: I like it +47 Vote: I do not like it

    Same result, can we practice together?

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4 years ago, # |
  Vote: I like it +23 Vote: I do not like it

Problem 8 is broken, nothing happens after one stone is left.

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    4 years ago, # ^ |
      Vote: I like it +3 Vote: I do not like it

    I wasted a lot of time checking the HTML,JS and APIs and was surprised to found that there was no condition written for the time you Win the Test. There was only one thing "You lack fundamentals shit"LOL ! Tim you owe my my Time :'((

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4 years ago, # |
  Vote: I like it +7 Vote: I do not like it

:(

sedlyf

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4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

tmw orz

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4 years ago, # |
  Vote: I like it +22 Vote: I do not like it

Where can I practice this type of questions?

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

its seems that problem 8 is broken

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    4 years ago, # ^ |
      Vote: I like it -9 Vote: I do not like it

    last 3 questions are impossible to ace due to bugs in 6 and 8 , giving Wrong answer intentionally (or doesn't have any answer) in problem 7.

    In problem 7 i am getting 1,3 from brute forces but still it's giving WA .

    Probably April fool :) Others can save their 30 minutes .

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      4 years ago, # ^ |
        Vote: I like it +11 Vote: I do not like it

      (1, 3) => (2, 6) => (4, 7) => (8, 8)

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        4 years ago, # ^ |
        ← Rev. 2   Vote: I like it 0 Vote: I do not like it

        is this your idea of april fool? you've got me man. I wasted 1 hour on this test.

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        4 years ago, # ^ |
          Vote: I like it 0 Vote: I do not like it

        problem 8 is broken. I got one stone left and nothing happened.

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          4 years ago, # ^ |
            Vote: I like it 0 Vote: I do not like it

          My fault... the client is initialized with the wrong number of stones so the server doesn't think that the problem was solved.

          If you press reset though, it will sync with the server.

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            4 years ago, # ^ |
              Vote: I like it 0 Vote: I do not like it

            i just tried,and it just start game from the begining and dont give me a accept like a correct answer

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            4 years ago, # ^ |
              Vote: I like it -28 Vote: I do not like it

            tmwilliamlin168 It still does not work! I scored 5, and i can score 6 easily if this problem works please reply asap i have 10 minutes left

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              4 years ago, # ^ |
                Vote: I like it 0 Vote: I do not like it

              Congratulations on your solution. Maybe you would find it quicker if you notice that after every turn all piles are left with either an even or odd number of stones...

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4 years ago, # |
  Vote: I like it +18 Vote: I do not like it

Wow i got free access to the course, Excited!

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Seems there's a bug in Matching Problem. I just selected random options and even after submitting the wrong answer, after I selected the correct one, it increased my score. I think that shouldn't be intended.

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4 years ago, # |
  Vote: I like it +57 Vote: I do not like it

Apparently I suck at games.

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

It seems wiiliam has changed last problem a bit to make it impossible .

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    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    yes it is impossible now, I ran complete search and no solution was found.

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4 years ago, # |
  Vote: I like it +13 Vote: I do not like it

Had fun playing with Bob and losing ;(

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4 years ago, # |
← Rev. 2   Vote: I like it +10 Vote: I do not like it

Thanks for the beta access, I'm very appreciate that!

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4 years ago, # |
← Rev. 2   Vote: I like it +13 Vote: I do not like it

why you require people having prior knowledge if this course is from zero to hero ?

Thanks but i am happy with content of Errichto and demoralizer

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    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it +8 Vote: I do not like it

    Its preregistration he want to give access to only the good . But did anyone scored above 5 .

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

-_-

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4 years ago, # |
  Vote: I like it +51 Vote: I do not like it

Problem 9: Prove or disprove P=NP

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4 years ago, # |
  Vote: I like it +15 Vote: I do not like it

I thought this was a serious post at first. Got me william!

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4 years ago, # |
  Vote: I like it +19 Vote: I do not like it

Best april fool prank ever! William orz!

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4 years ago, # |
  Vote: I like it +11 Vote: I do not like it

tmwilliamlin168 Nice April fool ! Problem 6 and 7 are not solvable (for 6 we can not make better than equal score) Last problem is glitched :/

I have 2 stones everywhere but I can't move anymore haha Nice prank haha :p

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4 years ago, # |
  Vote: I like it +40 Vote: I do not like it

I knew I was gonna do it!

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4 years ago, # |
  Vote: I like it +9 Vote: I do not like it

How to prove that there is always a solution for problem 7?

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    4 years ago, # ^ |
      Vote: I like it +19 Vote: I do not like it

    Proof by Lopsy

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    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it 0 Vote: I do not like it

    If you have a pair $$$(a, b)$$$, and you assume $$$a < b$$$, you can always make $$$a$$$ closer to $$$b$$$ by $$$1$$$ by doubling $$$a$$$ first, then $$$b$$$. Repeat this operation until they are equal.

    $$$(a, b) \rightarrow (2a, b + 1) \rightarrow (2a + 1, 2b + 2)$$$

    Edit: this solution is wrong

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      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      Doesn't this not work because

      $$$|(2a+1)-(2b+2)|=|2a-2b-1|$$$ isn't necessarily less than $$$|a-b|$$$.

      I think this is only true when $$$a-1<b<a-1/3$$$, which has no integer solutions.

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4 years ago, # |
← Rev. 3   Vote: I like it 0 Vote: I do not like it

Proof that no solution exists of problem 8 : https://ideone.com/XMlAcg

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    4 years ago, # ^ |
      Vote: I like it +32 Vote: I do not like it

    We can also see that overall we are adding 1 to the sum and subtracting 4 so apparently everytime we change the sum by 3.

    and the sum of given numbers is 35 which gives remainder as 2. It is only possible if sum%3 == 1

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4 years ago, # |
  Vote: I like it +16 Vote: I do not like it
After defeating Bob, you think that he's too easy of an opponent for you.

Uhhh... what?

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4 years ago, # |
  Vote: I like it +10 Vote: I do not like it

wow! the course is rlly good tmw, im gonna spend more time using it now especially bcuz the open is this weekend.

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4 years ago, # |
  Vote: I like it +3 Vote: I do not like it

I've tried multiple times on Firefox and chrome to click pre-register. It pops up another small tab and then suddenly disappears with nothing happening. Anyone encountered that problem?

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Was anyone able to solve anyone out of problem 6,7 and 8 ?

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    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    Were you able to attempt them? I tried to press things but the question was not interacting?

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      4 years ago, # ^ |
        Vote: I like it 0 Vote: I do not like it

      It was interacting

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        4 years ago, # ^ |
          Vote: I like it 0 Vote: I do not like it

        The problems are impossible(8 for sure, 6 and 7 don't know) William Lin was just trying to fool us.It was fun and the work he put into this is a lot. Anyway better than the rickroll he did in a long challenge once.

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          4 years ago, # ^ |
            Vote: I like it +1 Vote: I do not like it

          Yet he still manage to rickroll me this time (look at ur email).

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            4 years ago, # ^ |
              Vote: I like it +3 Vote: I do not like it

            yeah me too. Will we ever not fall for his traps :rofl: It was a well planned and perfectly executed rickroll though.

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    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it +8 Vote: I do not like it

    For problem 6 you can show that the 2nd player has a strategy that can always at least tie the first player.

    The blocks are of length 3,5,7,9.

    The 2nd player strategy is as follows.

    If the player 1 paints in either middle of any block, the 2nd player can paint the the middle of any one of the remaining blocks. Otherwise the 2nd player can paint tile on the same block that the 1st player painted symmetrically on the other end, a reflection over the center.

    The 2nd player will always have a reply for the 1st player and this repeats until the game is over.

    You can show that the 1st and 2nd player will always end up with the same number of segments. Although this isn't the strategy that was actually used, the strategy the computer uses probably works similarly.

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4 years ago, # |
  Vote: I like it +16 Vote: I do not like it

finally!

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4 years ago, # |
← Rev. 2   Vote: I like it +16 Vote: I do not like it

Waah bete mauj kar li.

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4 years ago, # |
  Vote: I like it +17 Vote: I do not like it

I just like the fact that I knew it's April Fools and proved that the games can't be won but still didn't stop me for playing them for 30 minutes for no reason

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4 years ago, # |
  Vote: I like it +10 Vote: I do not like it

Am I wrong or is the stone game really impossible to win!!?

Bob plays symmetrically unless you play center, in which case he plays center in one of the remaining centres (there are 4 so this is always possible).

In the end all non-centre cells are coloured symmetrically. Therefore center colours won't change the number of regions, which will be the same for blue and red, thus you can't win.

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    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    Ah wait lol, it really is an April Fools prank, well done!

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

editorial when?

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Is hacking into the server the only way to pass this test??? Too bad I don't know how :'(.

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4 years ago, # |
  Vote: I like it +5 Vote: I do not like it

Auto comment: topic has been updated by tmwilliamlin168 (previous revision, new revision, compare).

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    4 years ago, # ^ |
      Vote: I like it +16 Vote: I do not like it

    DO NOT SELL THE PERSONAL DATA IN DARK WEB!

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    4 years ago, # ^ |
      Vote: I like it +9 Vote: I do not like it

    You know you are going to hell for pranking so many people for 3 days straight

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4 years ago, # |
  Vote: I like it +16 Vote: I do not like it

The admissions committee has carefully reviewed your application. After much consideration, it is with great regret that we must inform you we are unable to offer you a spot in the beta course.

The course was extremely popular and there was a large number of strong applicants; in light of this, we were unable to offer a spot to every worthy applicant.

We recognize that this letter may come as a disappointment to you. Nevertheless, we encourage you to continue practicing competitive programming and wish you the best of luck in your future programming competitions.

Lastly, we would like to thank you for the time and effort you took to submit your application. We encourage you to review the solutions to the pre-registration test and subscribe for future updates.

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4 years ago, # |
  Vote: I like it +14 Vote: I do not like it

Though u pranked,but u were successful in getting an estimate on how many users are interested in your course or any other project like this. Well played.

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4 years ago, # |
  Vote: I like it +16 Vote: I do not like it

It's funny how I managed to get rick-rolled twice

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

https://course.williamlin.io/story

I decided it was time to send out decision letters to the 7000+ people who have pre-registered.

pog, i wonder how many people got rickrolled

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4 years ago, # |
  Vote: I like it +1 Vote: I do not like it

You got me with the last one. I didn't notice that it wasn't possible until I saw that you aren't allowed to perform the operation if any piles are empty. I don't have a proof for questions 6 or 7 being impossible but I'm convinced 6 isn't, and 7 is just too mathy for me to want to try that badly.

But fun joke, I enjoyed it!

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

Auto comment: topic has been updated by tmwilliamlin168 (previous revision, new revision, compare).

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