I can't understand it. Only 6 people have passed it in the contest.
→ Pay attention
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | jiangly | 3631 |
| 4 | Kevin114514 | 3574 |
| 5 | maroonrk | 3521 |
| 6 | strapple | 3515 |
| 7 | Radewoosh | 3461 |
| 8 | tourist | 3428 |
| 9 | turmax | 3378 |
| 10 | Um_nik | 3376 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 161 |
| 2 | adamant | 146 |
| 3 | Um_nik | 145 |
| 4 | Dominater069 | 142 |
| 5 | errorgorn | 140 |
| 6 | cry | 138 |
| 7 | Proof_by_QED | 136 |
| 8 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 10 | soullless | 133 |
→ Find user
→ Recent actions
Codeforces (c) Copyright 2010-2026 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Jun/01/2026 09:08:29 (g1).
Desktop version, switch to mobile version.
Supported by
Imagine tourist being unable to solve a 2100 problem...
Rating system gets a "WA on test case 1610" verdict
I think that if *2100 problems are in such difficulty like this, I will never become a master.
UPD : It was updated.
Maybe because there were blues among these 6 people...
But only 6 people have passed it in the contest
Maybe Mike just calculates average rating of these people
IMO it would be faulty logic -- if tourist makes an alt, and becomes the only one to solve the problem, that shouldn't make the problem get a 800 rating. Mike wouldn't have calculated it this way
That should be $$$\frac{3366+3315+2838+1772+1714+2236}{6}\approx 2540$$$. So the problem should at least get *2500.
Calculates average performance and not rating?
So calculating average rating is a type of wrong logic.
Even so, the rating I calculated(*2500) is higher than the actual rating(*2100).
I don't think so -- a newbie ACed 1610I and the problem got a normal 3300 rating
he_____hezhou may be hehezhou 's account.
likely, but then the system shouldn't be able to tell...
Also 1603F - October 18, 2017 is *2700 but only 3 people solved the problem officially
fun fact: OddImage said 1603F - October 18, 2017 is a classical and trivival problem.
I'm curious about the way to calculate the difficulty of problems... I don't think that it's reasonable.
It is now fixed. It is now 3100. Funny that the difference is a whole 1000 in rating.
MikeMirzayanov do you type the ratings in manually?