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| # | User | Rating |
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| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3611 |
| 4 | jiangly | 3583 |
| 5 | strapple | 3515 |
| 6 | tourist | 3470 |
| 7 | Radewoosh | 3415 |
| 8 | Um_nik | 3376 |
| 9 | maroonrk | 3361 |
| 10 | XVIII | 3345 |
| # | User | Contrib. |
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| 1 | Qingyu | 162 |
| 2 | adamant | 148 |
| 3 | Um_nik | 146 |
| 4 | Dominater069 | 143 |
| 5 | errorgorn | 141 |
| 6 | cry | 138 |
| 7 | Proof_by_QED | 136 |
| 8 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 10 | soullless | 133 |

Let $$$y_1$$$ be a point on the coordinate plane where $$$y_1$$$ is more optimal than some $$$y_j$$$.
This can only be true if $$$y_1 \cdot y_j \equiv 2 \text{ }(\text{mod } 10^9 + 7)$$$.
left as an exersise for the reader lol
Today we teach the ability to perform range queries in $$$\mathcal{O}(1)$$$, regardless of the query rekwaired.
Consider $$$Q = [l, r]$$$.
Iterate over all quadraubles $$$\left(a,b,c,d\right)$$$, add $$$Q[a]\times Q[b]\times Q[c] - Q[d]^2$$$
Now to solve single qwery, output $$$\text{Quadruble}[l][r^2][r-l^r][l+r^l]$$$.
The precomputation took $$$\mathcal{O}(1)$$$ time because $$$a,b,c,d\le 10^{18}$$$, a constant
You solve every query in $$$\mathcal{O}(1)$$$ cuz u immediately output the formula.
if you dont trust me, try it in this problem
you can see that my code is fastest ($$$0.00$$$ s)
actually the ones who will be in internation l olympiads of intormatica who will represant the united statat of amrika are
1- nor 2- Geothermal 3- xzm2024 4- awoo 5- Seryi 6- FerjaniSassi
they have officully qualified to the oio (olympiad international of intormatics), and they will participate offically
learn from the true red, this is how we write code https://mirror.codeforces.com/contest/4/submission/203467882
also people like Um_nik cant even be 1st because like they dont even know wavelet tree??? like it is so easy just make a tree
also a lot of people struggle to get to YELLOW which is the easiest rate to achieve,, because they write recursive segmant tree?? honestly go learn how to code...
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