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| 7 | Proof_by_QED | 136 |
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+9
First unrated educational round of 2022! :D |
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0
There will be at most five hundred interactive problems in the round, which means all problems might be interactive. That's interesting! |
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0
5 1 1 1 6 6 1 -> 5 1 1 6 6 6 1 // operate [4, 6] -> 5 5 5 5 5 5 1 // operate [1, 6] -> 5 5 5 5 5 5 5 // operate [1, 7] |
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+15
Try if this test is |
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0
Of course, we can't make sure we'll always find such $$$a$$$ and $$$b$$$ that $$$a + b \geq x + y + 1$$$. And at that time, the answer will be increased by 1, because whichever we select the $$$b$$$, we can't make $$$a + b \gt = x + y + 1$$$, in other world, the person who get the $$$a$$$ place in round 1 will finally placed before Nikolay. |
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0
The answer should in range [1,n]. |
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+24
For a number $$$a$$$ in round 1 and another number $$$b$$$ in round 2, we should make sure $$$a + b \geq x + y + 1$$$. $$$1$$$ should find $$$x + y$$$, $$$2$$$ should find $$$x + y - 1$$$... And if $$$x + y \gt n$$$, $$$1$$$ should find the smallest number in round 2 which can be selected. So, we can see that the final answer will be $$$x + y - n + 1$$$, cause we can not arrange number $$$[1, x + y - n]$$$ to make them greater than $$$x + y$$$, and don't forget the ans must in $$$[1,n]$$$.
In round 1, for each number $$$a$$$ between $$$1$$$ and $$$x-1$$$(it can be empty), we can find a number $$$b$$$ in round 2, and make $$$a + b \leq x + y$$$. In round 2, for each number $$$b$$$ between $$$1$$$ and $$$y-1$$$(it can be empty), we can find a number $$$a$$$ in round 1, and make $$$a + b \leq x + y$$$. We cannot find any other pairs to make $$$a + b \leq x + y$$$. Thus, the answer is $$$x - 1 + y - 1 + 1$$$, and don't forget the ans must in $$$[1,n]$$$. Let $$$a = x - 1, b = y + 1$$$, while $$$a$$$ is decreased by $$$1$$$, we can add $$$1$$$ for $$$b$$$. If $$$b$$$ is greater than $$$n$$$, we can select any number remaining, cause at this time, $$$a + b \lt x + y$$$. To proof the second one, we can just swap the round 1 and round 2. It seems like it's a kind of greedy, but the editorial can proof the answer strictly. And also sorry for my poor English. Wish it can help you. :D UPD: swap((a,b),(x,y)), sorry for the mistake. |
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+61
How to register as a team member... I can't see it... UPD: Fixed now, and wish everyone will enjoy the contest, GL & HF. |
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0
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0
That's amazing! And how about to add hack to the game? :) |
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+7
The time I showed was UTC+8, so I didn't notice the difference in the start time. |
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+26
The time is right for Chinese students! That's great! UPD: The Problem was fixed, and wish everyone will increase your rating. |
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+8
Chinese users will like it because of the time of the contest~ |
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