htoshiro is my love

you're still -98, not good enough to impress me

I'm not NSFW fyi

i wrote that myself

Don't apologize for being "dumb" — it's completely normal to have questions and misunderstandings! Let's break down the problem statement and your concerns:

Problem Statement: Given a permutation with some persistent swap queries, check if the permutation after each swap can form a DFS order of some perfect binary tree.

Your Concern: You think that as long as the permutation starts with 1, you can always recreate a perfect binary tree from the permutation. You're suggesting that by assigning a pointer p = 0 and traversing the binary tree, you can assign values to the nodes according to the permutation P.

Misunderstanding: The problem is not asking you to recreate a perfect binary tree from the permutation. Instead, it's asking you to verify whether the permutation after each swap can form a DFS order of some perfect binary tree. In other words, you need to check if the resulting permutation can be used as a DFS order of a perfect binary tree.

Key Point: The key point is that the DFS order of a perfect binary tree is not just about assigning values in the correct order. It's also about the structure of the tree. A perfect binary tree has a specific structure, where each node has at most two children (left and right). The DFS order should reflect this structure.

Correct Approach: To solve this problem, you need to check if the permutation after each swap can be used as a DFS order of a perfect binary tree. You can do this by iterating through the permutation and checking if each node has at most two children (left and right). You can also use a graph data structure to represent the binary tree and verify that it satisfies the properties of a perfect binary tree.

Hint: To simplify the problem, you can start by assuming that the permutation is initially a valid DFS order of a perfect binary tree. Then, you can apply the swap queries and check if the resulting permutation is still a valid DFS order of a perfect binary tree.

I hope this helps clarify things! If you have more questions or need further guidance, feel free to ask.

Goals beyond our understanding

no you wont, I bet

cuz he kakadiya

ummmmmmmmmmm..........