### desperateboy12344's blog

By desperateboy12344, history, 4 weeks ago,

As my title stated, I really need help with understanding D (https://mirror.codeforces.com/contest/2002). (Sorry, I'm really dumb :<<<). So the statement is like this (D1): Given a permutation with some persistent swap queries and a dfs algorithm, check if the permutation after each swap can form a dfs order of some perfect binary tree. I really think that as long as the permutation starts with 1, we can always recreate a perfect binary tree from the permutation. Because like if we assign a pointer p = 0, when we traverse on a binary tree, when we enter a node u, we can just assign p = p + 1, and then assign a[u] = P[p] (P is the original permutation), hence it always exists (Did I misread the statement??). Help me guys I'm really dumb :<<<

 » 4 weeks ago, # |   0 Don't apologize for being "dumb" — it's completely normal to have questions and misunderstandings! Let's break down the problem statement and your concerns:Problem Statement: Given a permutation with some persistent swap queries, check if the permutation after each swap can form a DFS order of some perfect binary tree.Your Concern: You think that as long as the permutation starts with 1, you can always recreate a perfect binary tree from the permutation. You're suggesting that by assigning a pointer p = 0 and traversing the binary tree, you can assign values to the nodes according to the permutation P.Misunderstanding: The problem is not asking you to recreate a perfect binary tree from the permutation. Instead, it's asking you to verify whether the permutation after each swap can form a DFS order of some perfect binary tree. In other words, you need to check if the resulting permutation can be used as a DFS order of a perfect binary tree.Key Point: The key point is that the DFS order of a perfect binary tree is not just about assigning values in the correct order. It's also about the structure of the tree. A perfect binary tree has a specific structure, where each node has at most two children (left and right). The DFS order should reflect this structure.Correct Approach: To solve this problem, you need to check if the permutation after each swap can be used as a DFS order of a perfect binary tree. You can do this by iterating through the permutation and checking if each node has at most two children (left and right). You can also use a graph data structure to represent the binary tree and verify that it satisfies the properties of a perfect binary tree.Hint: To simplify the problem, you can start by assuming that the permutation is initially a valid DFS order of a perfect binary tree. Then, you can apply the swap queries and check if the resulting permutation is still a valid DFS order of a perfect binary tree.I hope this helps clarify things! If you have more questions or need further guidance, feel free to ask.
•  » » 4 weeks ago, # ^ |   0 First of all thank you for answering my question.But I still don't really grasp it. In this example (https://mirror.codeforces.com/contest/2002/problem/D1)they say 1 3 5 4 2 6 7 can't be a dfs order of some perfect binary tree. But what about this treeAnyway thanks for your time!!
•  » » » 4 weeks ago, # ^ |   0 They're specifically talking about a perfect binary tree in which the parent of $i$ is $\left\lfloor\frac{i}{2}\right\rfloor$ for each $i$. This isn't true for your tree.
•  » » 4 weeks ago, # ^ |   +7 if you ever feel useless, remember that there are someone copy pasting people's questions into chatgpt and pasting the answer without changing a single word
•  » » » 4 weeks ago, # ^ |   0 I'm really desperate at solving this problem. Perhaps you can help me :>The AI guy wasted our 4 calorie and 3 brain cells.
•  » » » 4 weeks ago, # ^ |   0 i wrote that myself