| # | User | Rating |
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| 1 | Benq | 3792 |
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| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | adamant | 152 |
| 3 | Proof_by_QED | 146 |
| 3 | Um_nik | 146 |
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| 6 | errorgorn | 141 |
| 7 | cry | 139 |
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| 9 | TheScrasse | 134 |
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0
I hope that the late night debugging , early morning upsolving , day-night problem solving grind , gives you what you deserve :) this year. A very very happy new year all of you!!! |
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+1
for n=30 and k=4 , it fails.. answer should be 29 27 23 15 |
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-11
Geometryforces!!! :( |
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0
xD |
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0
I made the array (p) 0 to r then started iterating from r (i=r to 0) , calculated the number x which has opposite bits of i (for example if i=9 (1001) then x=6 (110)) then swapped p[i] and p[x] , and also maintained boolean array (if a number is already swapped once then it will not swapped again). Hope it helps :P |
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+4
though I guessed by intuition , each i from 1 to n-1 will have distance 2i , and n will have distance n. So the sequence would be like n , n-1 , n-2 , ..... , 1 , n , 1 , 2 , 3 , ..... n-1 |
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0
Guessforces! |
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0
Hoping that the small baby in my DP (display picture not dynamic programming ^_^) will smile till end of September :). |
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0
lol sad |
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0
<1400 , above 1400 rating , you can participate , but you will be out of competition (basically unrated) |
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+2
Hopefully I could be out of competition in the upcoming div4 :P |
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