| # | User | Rating |
|---|---|---|
| 1 | Benq | 3792 |
| 2 | VivaciousAubergine | 3647 |
| 3 | Kevin114514 | 3603 |
| 4 | jiangly | 3583 |
| 5 | strapple | 3515 |
| 6 | tourist | 3470 |
| 7 | dXqwq | 3436 |
| 8 | Radewoosh | 3415 |
| 9 | Otomachi_Una | 3413 |
| 10 | Um_nik | 3376 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | adamant | 152 |
| 3 | Proof_by_QED | 146 |
| 3 | Um_nik | 146 |
| 5 | Dominater069 | 144 |
| 6 | errorgorn | 141 |
| 7 | cry | 139 |
| 8 | YuukiS | 135 |
| 9 | chromate00 | 134 |
| 9 | TheScrasse | 134 |
|
+1
I Didnt understand what is meant by when it says your solution is hacked |
|
0
Its better to use Simple Binary search that would give you O(log n) time complexity in this the code can be : int BinarySearch(int arr[],int x,int n) { int low=0; int high=n; while(low<=high) { int mid=low+(high-low)/2; if(x<arr[low])
{
return low;
break;
}
if(x>=arr[high])
{
return high+1;
break;
}
if(x<arr[mid])
{
high=mid-1;
}
else if(x>=arr[mid])
{
low=mid+1;
}} this will surely give you the time complexity you need |
| Name |
|---|


